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Marina CMI [18]
3 years ago
13

Solve the inequality. c + 5 ≥ 10

Mathematics
1 answer:
anzhelika [568]3 years ago
6 0

Answer:

c≥5

Step-by-step explanation:

hope that helps :)

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Yes or No<br> The volume is the number of cubic units needed to fill a solid figure.
Mademuasel [1]
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2 years ago
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What is the net-price rate when a designer swimsuit, originally priced at $85 is discounted 25/60?
Gre4nikov [31]
Designer's swimsuit is originally priced at 85 dollars.
NOw, it applied a discount which is 25/60. First, let's find out how much the discount rate.
=> 25 / 60 = 0.42 * 100 = 42% is the discount.
=> 85 dollars * 0.42 = 35.7 is the discount.
=> 85 dollars - <span>35.7 dollars = 49.3 dollars is now the price.</span>
4 0
3 years ago
Suppose a population has a mean weight of 180 pounds and a standard deviation of 25 pounds. a sample of 100 items is drawn from
Angelina_Jolie [31]

Solution: We are given:

μ=180,σ=25,n=100

Therefore the standard error of the mean is

\frac{standard deviation}{\sqrt{n}}

\frac{25}{\sqrt{100}}

2.5

6 0
3 years ago
Ron has 24 coins with a total value of $3.00. The coins are nickels (5 cents) and quarters (25 cents). How many of each coin doe
Vesna [10]

Answer:

Ron has 15 nickels and 9 quarters

Step-by-step explanation:

Create a system of equations where n is the number of nickels and q is the number of quarters he has:

n + q = 24

0.05n + 0.25q = 3

Solve by elimination by multiplying the top equation by -0.25

-0.25n - 0.25q = -6

0.05n + 0.25q = 3

Add them together and solve for n:

-0.2n = -3

n = 15

So, Ron has 15 nickels. Find how many quarters he has by subtracting 15 from 24:

24 - 15

= 9

So, Ron has 15 nickels and 9 quarters.

3 0
3 years ago
Determine whether
lora16 [44]

Answer:

(a) and (b) are not equivalent

(c) is equivalent

Step-by-step explanation:

Given

\frac{25^m}{5}

Required

Determine an equivalent or nonequivalent expression

(a)\ 25^{m-1

We have:

25^{m-1

Apply law of indices

25^{m-1} = \frac{25^m}{25}

<em>This is not equivalent to </em>\frac{25^m}{5}<em></em>

(b)\ 25^{2m - 1}

We have:

25^{2m - 1}

Apply law of indices

25^{2m - 1} = \frac{25^{2m}}{25}

<em>This is not equivalent to </em>\frac{25^m}{5}<em></em>

<em></em>

<em />(c)\ 5^{2m-1}<em />

We have:

<em />5^{2m-1}<em />

Apply law of indices

<em />5^{2m-1} = \frac{5^{2m}}{5^1}<em />

<em />5^{2m-1} = \frac{5^{2m}}{5}<em />

<em>Evaluate the numerator</em>

<em />5^{2m-1} = \frac{25m}{5}<em />

<em />

<em>This is an equivalent expression</em>

4 0
2 years ago
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