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atroni [7]
3 years ago
13

Based on the triangles, which statement is true?

Mathematics
1 answer:
AlladinOne [14]3 years ago
4 0

The sum of interior angles of a triangle is 180°, and a linear pair is supplementary (adds to 180°). The appropriate choice is

... G. w = 105°, because ...

_____

In short, an exterior angle is equal to the sum of the opposite interior angles.

... w = 180 - (180 - (45 + 60)) = 180 -180 +45 +60

... w = 45 +60

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Step-by-step explanation??

6 0
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83. 6 in a complex number
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Answer:

83.6 is a real number

Step-by-step explanation:

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2/3 divide by 2/5<br><br> help please
suter [353]

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Explantion:

8 0
3 years ago
10 years ago, there were 35 mountain lions and today there are 21. Find the percent of change.
charle [14.2K]

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40%

Step-by-step explanation:

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4 0
3 years ago
In 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams.
jekas [21]

Answer:

1,805 kg.

Step-by-step explanation:

We have been given that in 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams. We are asked to find the how much the world's largest pumpkin weighs than an average pumpkin.

First of all, we will convert the weight of average pumpkin in kilograms by dividing 5,000 by 1000 as 1 kg equals 1,000 gm.

\text{The weight of average pumpkin}=\frac{5000\text{ gm}}{\frac{\text{1000 gm}}{\text{ 1 kg}}}

\text{The weight of average pumpkin}=5000\text{ gm}\times \frac{\text{ 1 kg}}{\text{1000 gm}}

\text{The weight of average pumpkin}=5\text{ kg}

Now, we will subtract the weight of average pumpkin from world's largest pumpkin's weight.

1,810\text{ kilograms}-5\text{ kilograms}=1,805\text{ kilograms}

Therefore, the 2010 world-record pumpkin weighs 1,805 kilograms more than an average-sized pumpkin.

3 0
3 years ago
Read 2 more answers
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