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3 years ago

Solve 5g = 20 Please and thank u

Mathematics

2 answers:

Eva8 [605]3 years ago

7 0

Answer:

g= 4

Step-by-step explanation:

5g = 20

5g /5 = 20 /5

g =4

Greeley [361]3 years ago

6 0

Answer:

g = 4

Step-by-step explanation:

5g = 20

Divide each side by 5

5g/5 = 20/5

g = 4

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Solve the inequality 2x>30+5/4x

insens350 [35]

Answer:

Step-by-step explanation:

$2x > 30+\frac{5}{4x} \\2x-\frac{5}{4x} > 30\\\frac{8x^2-5}{4x} > 30\\case~1\\if~x > 0\\8x^2-5 > 120x\\8x^2-120x > 5\\x^2-15x > \frac{5}{8} \\adding~(-\frac{15}{2} )^2~to~both~sides\\(x-\frac{15}{2} )^2 > \frac{5}{8}+\frac{225}{4} \\(x-\frac{15}{2} )^2 > \frac{455}{8} \\x-\frac{15}{2} < -\sqrt{\frac{455}{8} } \\x < \frac{15}{2}-\sqrt{\frac{455}{8} } \\or~x < 0\\rejected~as~x > 0$

$x-\frac{15}{2} > \sqrt{\frac{455}{8} } \\x > \frac{15}{2} +\sqrt{\frac{455}{8} }$

case~2

$if~x < 0\\8x^2-5 < 120x\\8x^2-120x < 5\\x^2-15x < \frac{5}{8} \\adding~(-\frac{15}{2} )^2\\(x-\frac{15}{2} )^2 < \frac{5}{8} +(-\frac{15}{2} )^2\\|x-\frac{15}{2} | < \frac{5+450}{8} \\-\sqrt{\frac{455}{8} } < x-\frac{15}{2} < \sqrt{\frac{455}{8} } \\\frac{15}{2} -\sqrt{\frac{455}{8} } < x < \frac{15}{2} +\sqrt{\frac{455}{8} } \\but~x < 0\\7.5-\sqrt{\frac{455}{8} } < x < 0$

8 0

1 year ago

What is 27% of 81 using the Decimals strategy?

NemiM [27]

27%=(27/100)=0.27

0.27*81=21.87

Hope this helps!!

4 0

3 years ago

Read 2 more answers

HELP ME OUT PLS!!!!!

miskamm [114]

Answer:

x = 26

Step-by-step explanation:

Supplementary angles mean that when the two angles are added together, they add up to 180. With this info, we can set the two expressions equal to 180

124 + (2x + 4) = 180.

128 + 2x = 180 combine like terms

2x = 52 subtract both sides by 128

x = 26. divide both sides by 2

5 0

2 years ago

Greatest common factor of 2, 15 , 6

ratelena [41]

Answer:Gcf=1.

Step-by-step explanation: The factors of 2 are: 1, 2 .

The factors of 6 are: 1, 2, 3, 6 .

The factors of 15 are: 1, 3, 5, 15.

3 0

3 years ago

The endpoints of the segment AB are A(-2,4) and B(4,0). Find the endpoints of the image after the segment is reflected over the

serious [3.7K]

Answer:

A' ( 2, 4) and B' ( -4, 0)

Step-by-step explanation:

A ( -2, 4) and B( 4,0) reflected over the y-axis

A' ( 2, 4) and B' ( -4, 0)

the y-coordinate do not change and the x is opposite sign

(x,y) reflected over y-axis (-x, y)

3 0

3 years ago