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noname [10]
3 years ago
7

Can somebody help me with this problem

Mathematics
1 answer:
maw [93]3 years ago
7 0
Can c it if i could i would help u tho
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What is 2.5 simplified
Nuetrik [128]

Step-by-step explanation:

2.5 =  \frac{25}{10}  =  \frac{5 \times 5}{2 \times 5}  =  \frac{5}{2}  \\

3 0
3 years ago
Health insurers are beginning to offer telemedicine services online that replace the common office visit. A company provides a v
Veronika [31]

Answer:

\text {CI} = (60.54, \: 81.46)\\\\

Therefore, we are 95% confident that actual mean savings for a televisit to the doctor is within the interval of ($60.54 to $81.46)

Step-by-step explanation:

Let us find out the mean savings for a televisit to the doctor from the given data.

Using Excel,

=AVERAGE(number1, number2,....)

The mean is found to be

\bar{x} = \$71  

Let us find out the standard deviation of savings for a televisit to the doctor from the given data.

Using Excel,

=STDEV(number1, number2,....)

The standard deviation is found to be

 s = \$ 22.35

The confidence interval is given by

\text {confidence interval} = \bar{x} \pm MoE\\\\

Where the margin of error is given by

$ MoE = t_{\alpha/2}(\frac{s}{\sqrt{n} } ) $ \\\\

Where n is the sample of 20 online doctor visits, s is the sample standard deviation and t_{\alpha/2} is the t-score corresponding to a 95% confidence level.

The t-score is given by is

Significance level = α = 1 - 0.95 = 0.05/2 = 0.025

Degree of freedom = n - 1 = 20 - 1 = 19

From the t-table at α = 0.025 and DoF = 19

t-score = 2.093

So, the margin of error is

MoE = t_{\alpha/2}(\frac{s}{\sqrt{n} } ) \\\\MoE = 2.093\cdot \frac{22.35}{\sqrt{20} } \\\\MoE = 2.093\cdot 4.997\\\\MoE = 10.46\\\\

So the required 95% confidence interval is

\text {CI} = \bar{x} \pm MoE\\\\\text {CI} = 71 \pm 10.46\\\\\text {CI} = 71 - 10.46, \: 71 + 10.46\\\\\text {CI} = (60.54, \: 81.46)\\\\

Therefore, we are 95% confident that actual mean savings for a televisit to the doctor is within the interval of ($60.54 to $81.46)

7 0
3 years ago
The arithmetic mean (average) of four numbers is 85. If the largest of these numbers is 97, find the mean of the remaining three
Margaret [11]

Answer:

81

Step-by-step explanation:

Let's do this systematically:

Four numbers: a, b, c, d

Whose mean is 85: \frac{a + b + c + d}{4} = 85

Whose largest number is 97: \frac{a + b + c + 97}{4} = 85

Lets solve for the other numbers:

a+b+c+97 = 85*4 = 340

340 - 97 = 243

a+b+c = 243

at this point it doesn't matter what the numbers are, they just need to add up to 243.

We can do 243÷3=81, which is our answer

3 0
3 years ago
PLS HELPPPP ILL GIVE BRAINLIEST HELP HELP
mojhsa [17]

Answer:B

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Please sleep me helpppp
defon

Answer:

help me first on this question

Step-by-step explanation:

5 0
3 years ago
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