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irina1246 [14]
3 years ago
6

The product of a number and five is at the most 30. List this as an inequality (less than,greater than,lessthanorequalto,moretha

norequalto,ect.) THE FASTEST ANSWER GETS 15 POINTS AND BRAINLIEST ANSWER THANKS
Mathematics
1 answer:
mixer [17]3 years ago
7 0
=6? I believe that's the answer give me a minute
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Calculate The scale factor of XYZ to you UVW enter answers as a whole number as a fraction in lowest terms using the slash mark
Lelu [443]

Answer:

Scale factor of ΔXYZ to ΔUVW will be 1/5

Step-by-step explanation:

Since all the angles of ΔXYZ and ΔUVW are equal, both the triangles will be similar.

ΔXYZ ~ ΔUVW

Since both the triangles are similar, ratio of the corresponding sides will be in the same ratio.

\frac{UV}{XY}=\frac{VW}{YZ}=\frac{UW}{XZ}

And the scale factor = \frac{\text{Side of UVW}}{\text{Side of XYZ}}

                                  = \frac{UV}{XY}

                                  = \frac{12}{60}

                                  = \frac{1}{5}

Therefore, scale factor of ΔXYZ to ΔUVW will be 1/5

5 0
3 years ago
What is the distance between -7 and 3
Masteriza [31]

Answer: 10

Step-by-step explanation:

7 0
3 years ago
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The authors of the articles of confederation wanted to
Jobisdone [24]
The authors of the articles of confederation wanted to preserve the land. They also wanted to create a weak goverment
4 0
4 years ago
The longest frontier between countries is between the u.s and Canada a distance of 3,987 miles how many weeks would it take some
Step2247 [10]
10 mins = 1 miles
1 hour = 1 x 6 = 6 miles
8 hours = 6 x 8 = 48miles

The jogger could cover 48 miles a day.

3987 ÷ 48 = 83.06 days

It takes 83.06 days to jog the length of this frontier.

83.06 days ÷ 7 = 11.87 weeks = 12 weeks (round to the nearest whole number)

It takes 12 weeks to jog the length of this frontier.
8 0
3 years ago
The weight (in pounds) w=f(d) of an object varies inversely as the square of its distance (in thousands of miles) d from the cen
yuradex [85]
The joint variation that is given in the problem above can be expressed as follows:
                                    w = k/d²
where w is the weight, k is the variation constant, and d is the distance from the center of the earth. Substituting the first scenario to obtain the value of k,
                                     160 = k/(4000)²
                                        k = 2.56 x 10^9
Using this value for the second scenario,
                                       w = (2.56 x 10^9) / (8,000)² = 40 lbs
Thus, the weight of the man, 8000 miles above the center of the earth is 40 lbs. 
5 0
3 years ago
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