Answer:
CE..AE...Segment addition postulate
Step-by-step explanation:
i got these answers from the quiz
Answer:
x=6
Step-by-step explanation:
Since this is a right triangle we can use the Pythagorean theorem
a^2 + b^2 = c^2
where a and b are the legs and c is the hypotenuse
x^2 + (x+2)^2 = (2x-2)^2
FOIL (x+2)^2 = x^2 +2x+2x+4 = x^2 +4x+4
FOIL (2x-2)^2 = 4x^2 -4x -4x+4 = 4x^2 -8x+4
Replacing these in to the equation
x^2 +x^2 +4x+4 = 4x^2 -8x+4
Combine like terms
2x^2 +4x +4 = 4x^2 -8x +4
Subtract 4 from each side
2x^2 +4x +4-4 = 4x^2 -8x +4-4
2x^2 +4x = 4x^2 -8x
Subtract 2x^2 from each side
2x^2 -2x^2+4x = 4x^2-2x^2 -8x
4x = 2x^2 -8x
Subtract 4x from each side
4x-4x = 2x^2 -8x-4x
0 = 2x^2 -12x
Factor out a 2x
0 = 2x(x-6)
Using the zero product property
2x =0 x-6 =0
x =0 x-6+6 = 0+6
x = 0 c=6
Nope.
They don't meet the requirements of the triangle inequality.
2.1 + 4 = 6.1 < 7.9
The triangle inequality requires the sum of any two sides be greater than the third side.
Answer:
90%
Step-by-step explanation:
50%×2 100%
5%×2 10%
45%×2 90%
Answer:
See below ↓↓
Step-by-step explanation:
<u>Finding the radius</u>
- C = 2πr
- 25 = 2 x 3.14 x r
- r = 25 / 6.28
- r = 3.98 cm ≅ 4 cm
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<u>Surface Area</u>
- 4πr²
- 4 x 3.14 x 4 x 4
- 3.14 x 64
- 200.96
- <u>201 cm²</u>
<u></u>
<u>Volume</u>
- 4/3πr³ = 4πr² x r/3
- 201 x 4/3
- 67 x 4
- <u>268 cm³</u>