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lina2011 [118]
3 years ago
11

How do you factor 9x^3 + 64 (Please show steps)

Mathematics
1 answer:
Novosadov [1.4K]3 years ago
8 0

First, let's review the formula for the "sum of two cubes:"

a^3 + b^3 = (a + b)(a^2 - ab + b^2).

Unfortunately, 9 is not a perfect cube. The cube root of 9 is 9^(1/3), and the square of the cube root of 9 is therefore 9^(2/3).

Thus,

9x^3 + 64 = (9^(1/3)*x + 4) * (9^(2/3)x^2 - 4*9^(1/3) + 16)

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Y=7x-24<br> Y=-3x+16 jakaj
Helen [10]
Y =  7x - 24
<u>y = -3x+ 16</u>
2y = 4x - 8
<u>2y</u> = <u>4x - 8
</u> 2        <u /> 2  <u>
</u>y = 2x - 4
 2x - 4 = 7x - 24
<u>-2x        -2x        </u>
       -4 = 5x - 24
<u>    +24         +24</u>
      20 = 5x
      <u>20</u> = <u>5x</u>
       5      5
        4 = x
y = 2x - 4
y = 2(4) - 4
y = 8 - 4
y = 4
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<u />
7 0
3 years ago
Sales tax in Nevada is 8.15%. If an item costs $167 before tax, how much tax would you pay on that item? (Enter your answer with
nordsb [41]
The tax would be $13.61
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Read 2 more answers
A small radio transmitter broadcasts in a 30 mile radius. If you drive along a straight line from a city 33 miles north of the t
Paha777 [63]

Answer:

34.26miles from 49.58miles of the drive (69.11% of the drive).

Step-by-step explanation:

A problem of Analytic Geometry. This question can be solved using  the resulting values from equaling the equations of the line (for the drive) and circle (with radius equals 30miles for radio transmitter broadcasting), and calculating the total distances from coincident points between circle and line, and total drive.

A graph is attached showing part of the circle and line with coincident points.

<h3>Line's Equation</h3>

Assuming transmitter is located (0, 0). From a city 33 miles north of the transmitter (0, 33) to a second city 37 miles east of the transmitter (37, 0).

Then, the equation for the line is (taking the two points from the start to the end):

\\ y-y_{1}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}*(x-x_{1})

\\ y-33=\frac{0-33}{37-0}*(x-0)}

\\ y-33=\frac{-33}{37}*x}

\\ y=\frac{-33}{37}*x} + 33 [1]

<h3>Circle's Equation</h3>

The equation for the circle whose center (0, 0) is:

\\ (x-0)^2 + (y-0)^2 = 30^2

\\ x^2 + y^2 = 30^2

\\ y^2 = 30^2 - x^2

\\ y = \frac{+}{-}\sqrt{30^2- x^2} [2]

Equaling [1] and [2], to determine the points where starting to receive the radio transmitter signals to the point where finishing those signals:

\\ \frac{-33}{37}*x + 33 = \sqrt{30^2- x^2}

Solving this equation for <em>x</em>, we have two solutions for it (from <em>WolframAlpha</em>):

\\ x_{1} = 40293/2458 - (111 \sqrt(80151))/2458 \approx 3.60775

\\ x_{2} = 40293/2458 + (111 \sqrt(80151))/2458 \approx 29.1774

Then, using [1], the corresponding values for <em>y</em> are:

\\ y_{1}=\frac{-33}{37}*(3.60775) \approx 29.78

\\ y_{2}=\frac{-33}{37}*(29.1774) \approx 6.97

So,

\\ (x_{1}=3.61, y_{1}=29.78)

\\ (x_{2}=29.18, y_{2}=6.97)

Well, the distance of the drive is:

\\ d = \sqrt{(x_{2}-x_{1})^2 + (y_{2}-y_{1})^2}

\\ d = \sqrt{(29.18-3.61)^2 + (6.97-29.78)^2}

\\ d \approx 34.2654 miles.

The total distance traveled is:

\\ d = \sqrt{(37-0)^2 + (0-33)^2}

\\ d \approx 49.5782 miles

Thus, during the drive, the signal of the radio transmitter was picked up for 34.26miles from the total of the 49.58 traveled, that is, a fraction equivalent to \\ \frac{34.2654}{49.5782} \approx 0.6911 or 69.11% of the drive.

4 0
3 years ago
Please help!! thank you
shutvik [7]

Answer: 5

Step-by-step explanation:

f(x)=3-x

f(-2)=3-(-2)

f(-2)=3+2

f(-2)=5

Hope this helps!! :)

Please let me know if you have any question

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3 years ago
A survey was taken of students at Utah High school to see how many students will attend the soccer game tonight. The principal s
makkiz [27]

Answer:

750

Step-by-step explanation:

5 0
3 years ago
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