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AnnyKZ [126]
3 years ago
10

A rectangular pyramid has a length of 14 centimeters, a width of 9 centimeters, and a height of 10 centimeters. explain the effe

ct on the volume of each dimension were doubled.
Mathematics
1 answer:
klemol [59]3 years ago
3 0
The volume of a rectangular pyramid = 1/3 ×Area×height
=1/3×L×W×H
if the dimensions were doubled
therefore,
V=1/3 × (9×2)×(14×2)×(10×2)
=1/3×18×28×20
=3360 cubic centimetres
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Given: m∠AKB = 25°
dexar [7]

Answer:

V = 255.98189 pi

SA = 172.64114π

Step-by-step explanation:

The first thing to do is find the radius.

the measure of angle AKO = 1/2 the measure of angle AKB

m< AKO = 12.5 degrees

Now use trig to find AO (aka the radius)

tan(12.5) = AO/25

AO = 25* tan(12.5)

<em>I'm leaving it like this to get a more accurate number</em>

Now to find the volume

the volume of a cone is pir^2h/3

plugging everything in we get:

pi(25*tan(12.5))^2 * 25/3

which is about <u>255.98189 pi</u>

Now for surface area

(this is the moment I realize symbols exist)

SA = πr(r+√h²+r²)

plugging everything in we have

π(25tan(12.5))((25tan(12.5)+√625+(25tan(12.5))^2)

<em>I know it looks like a lot but that's mainly because I left the radius as 25tan(12.5)</em>

The Surface Area is about <u>172.64114π</u>

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