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Valentin [98]
3 years ago
10

Write the equation of the line that passes through the points (7, —4) and (—1 , 3) , first in point -slope form , and then slope

- intercept form
Mathematics
1 answer:
ipn [44]3 years ago
5 0

Answer:

The slope of the line is -7/8

The point slope-form is y+4=(-7/8)(x-7)

The slope-intercept form is y=(-7/8)x+(17/8)

Step-by-step explanation:

You have to find the slope first using m=y2-y1 divided by x2-x1. After you found the slope of the line, you use one of the points to plug it into the point-slope form which is y-y1=m(x-x1). After you have done that, you would have convert this equation into slope-intercept form which is y=mx + b. In order to convert it, you have to multiply m with x and x1. Then you would have to get rid of y1 by doing the opposite of what y1 is. Finally, you would take the opposite of y1 and add it to the other side of the equation.

Really hope this helps! :)

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Can you please help with these questions? I need to finish homework by tonight.
noname [10]
Length x width is the formula.
so 18 x 18 for 7.
22 x 24 for 8.
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3 0
3 years ago
Mike spent half of his allowance going to the movies. He washed the family cat and earned $7. What is his weekly allowance if he
Natasha_Volkova [10]
16 - 7 is 9
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4 0
3 years ago
Is A ABC similar to DEF? Why or why not?
vova2212 [387]

Answer:

Option(D)

Step-by-step explanation:

Given are the two triangles, that are ABC and DEF, in which AB=8ft, DE=6ft, AC=10ft and DF=7.5ft.

For the two triangles to be similar, it must satisfy the similarity condition that is:

Both the triangles must have congruent angles and the sides should be proportional. Since, two sides of the given triangles are not proportional.Moreover, ∠A=25° and ∠D=24° which are not equal and ∠C=60° and ∠F=61° which are also not equal.

Therefore, Not all the angles are congruent, thus the triangles cannot be similar.

6 0
3 years ago
Read 2 more answers
Which of the following graphs shows the solution set for the inequality below? 3|x + 1| < 9
Bas_tet [7]

Step-by-step explanation:

The absolute value function is a well known piecewise function (a function defined by multiple subfunctions) that is described mathematically as

                                 f(x) \ = \ |x| \ = \ \left\{\left\begin{array}{ccc}x, \ \text{if} \ x \ \geq \ 0 \\ \\ -x, \ \text{if} \ x \ < \ 0\end{array}\right\}.

This definition of the absolute function can be explained geometrically to be similar to the straight line   \textbf{\textit{y}} \ = \ \textbf{\textit{x}}  , however, when the value of x is negative, the range of the function remains positive. In other words, the segment of the line  \textbf{\textit{y}} \ = \ \textbf{\textit{x}}  where \textbf{\textit{x}} \ < \ 0 (shown as the orange dotted line), the segment of the line is reflected across the <em>x</em>-axis.

First, we simplify the expression.

                                             3\left|x \ + \ 1 \right| \ < \ 9 \\ \\ \\\-\hspace{0.2cm} \left|x \ + \ 1 \right| \ < \ 3.

We, now, can simply visualise the straight line,  y \ = \ x \ + \ 1 , as a line having its y-intercept at the point  (0, \ 1) and its <em>x</em>-intercept at the point (-1, \ 0). Then, imagine that the segment of the line where x \ < \ 0 to be reflected along the <em>x</em>-axis, and you get the graph of the absolute function y \ = \ \left|x \ + \ 1 \right|.

Consider the inequality

                                                    \left|x \ + \ 1 \right| \ < \ 3,

this statement can actually be conceptualise as the question

            ``\text{For what \textbf{values of \textit{x}} will the absolute function \textbf{be less than 3}}".

Algebraically, we can solve this inequality by breaking the function into two different subfunctions (according to the definition above).

  • Case 1 (when x \ \geq \ 0)

                                                x \ + \ 1 \ < \ 3 \\ \\ \\ \-\hspace{0.9cm} x \ < \ 3 \ - \ 1 \\ \\ \\ \-\hspace{0.9cm} x \ < \ 2

  • Case 2 (when x \ < \ 0)

                                            -(x \ + \ 1) \ < \ 3 \\ \\ \\ \-\hspace{0.15cm} -x \ - \ 1 \ < \ 3 \\ \\ \\ \-\hspace{1cm} -x \ < \ 3 \ + \ 1 \\ \\ \\ \-\hspace{1cm} -x \ < \ 4 \\ \\ \\ \-\hspace{1.5cm} x \ > \ -4

           *remember to flip the inequality sign when multiplying or dividing by

            negative numbers on both sides of the statement.

Therefore, the values of <em>x</em> that satisfy this inequality lie within the interval

                                                     -4 \ < \ x \ < \ 2.

Similarly, on the real number line, the interval is shown below.

The use of open circles (as in the graph) indicates that the interval highlighted on the number line does not include its boundary value (-4 and 2) since the inequality is expressed as "less than", but not "less than or equal to". Contrastingly, close circles (circles that are coloured) show the inclusivity of the boundary values of the inequality.

3 0
3 years ago
Given m||n, find the value of x and y
34kurt
<h2>Answer: </h2><h3> x=15 & y=52</h3>

Hope this might help you (•.•) :)

4 0
3 years ago
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