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3 years ago

Find the slope and y-intercept of the graph of the equation. show your work please.

Mathematics

1 answer:

choli [55]3 years ago

5 0

Answer:

<h2>A. the slope is 8.</h2><h2>A. the y-intercept is 1</h2>

Step-by-step explanation:

The slope-intercept form of an equation of a line:

y = mx + b

m - slope

b - y-intercept

We have the equation y = 8x + 1.

Therefore:

m = 8, b = 1

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What is the equation of the graphed line written in standard form?

Dmitry_Shevchenko [17]

Answer:

Step-by-step explanation:

4 0

3 years ago

Ben drove 350 miles in 6 1/2 hours Marcie drove 520 miles on 12 1/4 hours who drove faster

natka813 [3]

Answer:

Ben drove faster

Step-by-step explanation:

350 miles / 6.5 hours = 53.84 miles per hour

<h2>MARCIE:</h2>

520 miles / 12.25 hours = 42.44 miles per hour

53.84 is faster than 42.44 therefore Ben is faster.

8 0

3 years ago

Please help show work too please thank you

Black_prince [1.1K]

(3x-9) +(x+19)+x=180
5x+10=180
-10=-10
5x=170
5 = 5
x=34

2x+(2x+10)+x=180
5x+10=180
-10=-10
5x=170
5 = 5
x=34

yes they are similar

6 0

3 years ago

Select TWO values of x that are roots

Sauron [17]

$x_1=\dfrac{-b-\sqrt{b^2-4ac}}{2a};\ x_2=\dfrac{-b+\sqrt{b^2-4ac}}{2a}\\\\y=x^2+3x+5\\\\a=1;\ b=3;\ c=5\\\\b^2-4ac=3^2-4(1)(5)=9-20=-11\\\\x_1=\dfrac{-3-\sqrt{-11}}{2\cdot1}=\dfrac{-3-\sqrt{-11}}{2}\\\\x_2=\dfrac{-3+\sqrt{-11}}{2}$

Answer: A and B.

3 0

3 years ago

Read 2 more answers

At what values of x does f(x) = x^3 - 2x^2 -4x+1 satisfy the mean value theorwm on [0,1]

denis-greek [22]

Answer:

x=1/3

Step-by-step explanation:

A function f is given as

$f(x) = x^3-2x^2-4x+1$ in the interval [0,1]

This function f being an algebraic polynomial is continuous in the interval [0,1] and also f is differntiable in the open interval (0,1)

Hence mean value theorem applies for f in the given interval

$f(1) = 1-2-4+1 = -4\\f(0) = 1$

The value

$\frac{f(1)-f(0)}{1-0} =\frac{-4-1}{1} =-5$

Find derivative for f

$f'(x) = 3x^2-4x-4$

Equate this to -5 to check mean value theorem

$3x^2-4x-4=-5\\3x^2-4x+1=0\\\\(x-1)(3x-1) =0\\x= 1/3 : x = 1$

We find that 1/3 lies inside the interval (0,1)

4 0

3 years ago