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Cerrena [4.2K]
3 years ago
9

Please help me with 11th grade math // Geometry ​

Mathematics
1 answer:
ohaa [14]3 years ago
5 0

Answer:

I sent I the answers on ur account

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What is the perimeter of the figure in the diagram (round to three decimal places if necessary)?
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Perimeter (p) = length around a shape.
So any horizontal sides we can add based upon their length in x-values and any vertical sides we can add based upon their length in y-values. The diagonal sides we can find by the distance formula:
d =  \sqrt{( {(x2 - x1)}^{2}  +  {(y2 - y1)}^{2} }
So the bottom base goes from x=1 to x=8, then up 1, right 1, and up from y=3 to y=9, then left from x=9 to x=6, down from y=9 to y=6, left from x=6 to x=3.
So far that is: (8-1)+1+1+(9-3)+(9-6)+(9-6)+(6-3)
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Now for the diagonal:
d =  \sqrt{( {(x2 - x1)}^{2}  +  {(y2 - y1)}^{2}) }  \\  =  \sqrt{( {(3- 1)}^{2}  +  {(6 - 2)}^{2} )}  \\  =  \sqrt{( {2}^{2}  +  {4}^{2} )}  =  \sqrt{(4 + 16)} \\  =  \sqrt{20} = 2 \sqrt{5}  = 4.47
P = 24 + 4.47 = 28.47
D) 28.472

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3 years ago
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34 is the answer

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4 years ago
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