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OleMash [197]
3 years ago
14

If 5x a number is decreased by twelve n the result is 108 wat is the number

Mathematics
1 answer:
Vesnalui [34]3 years ago
4 0

Answer:

The answer is 24.

Step-by-step explanation:

To find the unknown number, add 12 to 108 to get 120. Then, divide 120 by 5 to get 24.

To check if this is correct, multiply 5 and 24 to get 120, and then subtract 12 from 120 to get 108.


I hope this helped! :-)

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Answer:

1. Multiply the value of the first variable by one of the original equations to solve for the second variable.

2. Solve for one of the variables.

3. Substitute the value of the known variable into one of the original equations to solve for the unknown variable.

Step-by-step explanation:

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2. Check the boxes for the following sets that are closed under the given
son4ous [18]

The properties of the mathematical sequence allow us to find that the recurrence term is 1 and the operation for each sequence is

   a) Subtraction

   b) Addition

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   d) in this case we have two possibilities

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The sequence is a set of elements arranged one after another related by some mathematical relationship. The elements of the sequence are called terms.

The sequences shown can be defined by recurrence relations.

Let's analyze each sequence shown, the ellipsis indicates where the sequence advances.

a) ... -7, -6, -5, -4, -3

We can observe that each term has a difference of one unit; if we subtract 1 from the term to the right, we obtain the following term

        -3 -1 = -4

        -4 -1 = -5

        -7 -1 = -8

Therefore the mathematical operation is the subtraction.

b) 0. \sqrt{1}. \sqrt{4}, \sqrt{9}, \sqrt{16}, \sqrt{25}  ...

In this case we can see more clearly the sequence when writing in this way

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each term is found by adding 1 to the current term,

      \sqrt{(0+1)^2} = \sqrt{1^2} \\\sqrt{(1+1)^2} = \sqrt{2^2}\\\sqrt{(2+1)^2} = \sqrt{3^2}\\\sqrt{(5+1)^2} = \sqrt{6^2}

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      The recurrence term is unity, with the fact that the sequence extends to the right and to the left the operation is

  • To move to the right add 1

           -\frac{-10}{2} + 1 = \frac{-10}{2}  -   \frac{2}{2}  = \frac{-8}{2}\\\frac{-8}{2} + \frac{2}{2} = \frac{-6}{2}

  • To move left subtract 1

         \frac{-2}{2} - 1 = \frac{-4}{2}\\\frac{-4}{2} - \frac{2}{2} = \frac{-6}{2}

         

Using the properties the mathematical sequence we find that the recurrence term is 1 and the operation for each sequence is

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   d) This case we have two possibilities

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Learn more here: brainly.com/question/4626313

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Answer:

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Answer:

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