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kvv77 [185]
3 years ago
14

Select the correct answer.

Mathematics
1 answer:
forsale [732]3 years ago
3 0

Answer:

g=3

Step-by-step explanation:

f(g)=g²+3g

Personally, I would do a guess and check to figure this out.

Let's try a number like 3. Insert it -

f(3)=3²+3(3) =9+9=18

Therefore, the answer is 3.

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An acute angle θ is in a right triangle with cos θ = 9/10 . What is the value of sec θ?
xenn [34]

By definition

... sec(θ) = 1/cos(θ) . . . . trig identity

... sec(θ) = 1/(9/10) . . . . substitute the given value, then simplify to ...

... sec(θ) = 10/9

8 0
3 years ago
Read 2 more answers
Kala must choose a shirt, a pair of pants, and a cap for today's outfit. She has 3 shirts, 3 pairs of pants, and 1 cap to choose
Mrac [35]

Answer:

just multiply all the variables.

3 pants times 3 shirts= 9.

only 1 hat, so no variable there.

9 outfits

8 0
3 years ago
Where can the prpendicular bisectors of an acute triangle intersect?
ch4aika [34]
<span>The meeting point of the 3 </span>perpendicular bisectors<span> of a triangle's sides is called </span><span>the circumcenter.
</span><span><span>The circumcenter of an </span>acute triangle<span> is always </span>inside<span> the triangle.
so the answer is "a"

Source:
http://www.1728.org/trictr.htm
</span> 
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8 0
4 years ago
Help!!<br> With this question <br> Please
Sedbober [7]
<h2>Answer:</h2>

<u>The length is</u><u> 250 meters</u>

<h2>Step-by-step explanation:</h2>

If we look at the left corner of the diagram we see a scale. According to the scale factor of the map

1 cm :1000 cm

The length of the lap on the map is 25 cm

So (25 × 1000) = 25000 cm

Since

1 meter = 100 centimeter

So the actual length of the lap = 25000 ÷ 100 = 250 meters

3 0
3 years ago
Read 2 more answers
The distance between the goals on a soccer field is 52 meters. Each goal has a box that extends 5.49 meters into the field.What
Korvikt [17]

Answer:

41.02 meters.

Step-by-step explanation:

See the attached diagram.

The distance between the goals of a soccer field is 52 meters. Each goal has a box that extends 5.49 meters into the field.

If the distance from the front of the box at one end of the field to the front of the box at the other end of the field is x meters, then we can write the equation as

5.49 + x + 5.49 = 52

⇒ x + 10.98 = 52

⇒ x = 41.02 meters. (Answer)

7 0
4 years ago
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