<span>2−<span>5<span>(<span>3−<span>(<span><span>3^2</span>+5</span>)</span></span>)
do 3^2 </span></span></span><span>=<span>2−<span>5<span>(<span>3−<span>(<span>9+5</span>)</span></span>)
9+5</span></span></span></span><span>=<span>2−<span>5<span>(<span>3−14</span>)
3-14</span></span></span></span><span>=<span>2−<span><span>(5)</span><span>(<span>−11</span>)
multiply 5*11</span></span></span></span><span>=<span>2−<span>(<span>−55</span>)
negative cancels out then you do 2+55</span></span></span><span>=<span>57</span></span>
Answer:
f(x)=-18x^2
Step-by-step explanation:
Given:
1+Integral(f(t)/t^6, t=a..x)=6x^-3
Let's get rid of integral by differentiating both sides.
Using fundamental of calculus and power rule(integration):
0+f(x)/x^6=-18x^-4
Additive Identity property applied:
f(x)/x^6=-18x^-4
Multiply both sides by x^6:
f(x)=-18x^-4×x^6
Power rule (exponents) applied"
f(x)=-18x^2
Check:
1+Integral(-18t^2/t^6, t=a..x)=6x^-3
1+Integral(-18t^-4, t=a..x)=6x^-3
1+(-18t^-3/-3, t=a..x)=6x^-3
1+(6t^-3, t=a..x)=6x^-3
That looks great since those powers are the same on both side after integration.
Plug in limits:
1+(6x^-3-6a^-3)=6x^-3
We need 1-6a^-3=0 so that the equation holds true for all x.
Subtract 1 on both sides:
-6a^-3=-1
Divide both sides by-6:
a^-3=1/6
Raise both sides to -1/3 power:
a=(1/6)^(-1/3)
Negative exponent just refers to reciprocal of our base:
a=6^(1/3)
The answer is 12 ÷ 4 + 13 > 2 + 22 ÷ 2
There are 10 sides becuase the equation set up is 
and equal it to 144.
Solve for n and get 10
