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romanna [79]
4 years ago
11

Write the rational number as a decimal -21/16

Mathematics
1 answer:
Ierofanga [76]4 years ago
7 0
- \frac{21}{16} = \boxed{\bf{1.3125}}
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A common assumption in modeling drug assimilation is that the blood volume in a person is a single compartment that behaves like
mixas84 [53]

Answer:

a) \mathbf{\dfrac{dx}{dt} = 30 - 0.015 x}

b) \mathbf{x = 2000 - 2000e^{-0.015t}}

c)  the  steady state mass of the drug is 2000 mg

d) t ≅ 153.51  minutes

Step-by-step explanation:

From the given information;

At time t= 0

an intravenous line is inserted into a vein (into the tank) that carries a drug solution with a concentration of 500

The inflow rate is 0.06 L/min.

Assume the drug is quickly mixed thoroughly in the blood and that the volume of blood remains constant.

The objective of the question is to calculate the following :

a) Write an initial value problem that models the mass of the drug in the blood for t ≥ 0.

From above information given :

Rate _{(in)}= 500 \ mg/L  \times 0.06 \  L/min = 30 mg/min

Rate _{(out)}=\dfrac{x}{4} \ mg/L  \times 0.06 \  L/min = 0.015x \  mg/min

Therefore;

\dfrac{dx}{dt} = Rate_{(in)} - Rate_{(out)}

with respect to  x(0) = 0

\mathbf{\dfrac{dx}{dt} = 30 - 0.015 x}

b) Solve the initial value problem and graph both the mass of the drug and the concentration of the drug.

\dfrac{dx}{dt} = -0.015(x - 2000)

\dfrac{dx}{(x - 2000)} = -0.015 \times dt

By Using Integration Method:

ln(x - 2000) = -0.015t + C

x -2000 = Ce^{(-0.015t)

x = 2000 + Ce^{(-0.015t)}

However; if x(0) = 0 ;

Then

C = -2000

Therefore

\mathbf{x = 2000 - 2000e^{-0.015t}}

c) What is the steady-state mass of the drug in the blood?

the steady-state mass of the drug in the blood when t = infinity

\mathbf{x = 2000 - 2000e^{-0.015 \times \infty }}

x = 2000 - 0

x = 2000

Thus; the  steady state mass of the drug is 2000 mg

d) After how many minutes does the drug mass reach 90% of its stead-state level?

After 90% of its steady state level; the mas of the drug is 90% × 2000

= 0.9 × 2000

= 1800

Hence;

\mathbf{1800 = 2000 - 2000e^{(-0.015t)}}

0.1 = e^{(-0.015t)

ln(0.1) = -0.015t

t = -\dfrac{In(0.1)}{0.015}

t = 153.5056729

t ≅ 153.51  minutes

4 0
3 years ago
Bác lan thu hoạch được 10 tạ gạo nếp và 1,5 tấn gạo tẻ. hỏi bác lan thu được tất cả bao nhiêu tạ gạo
olga55 [171]

Answer:

I Don't understand please

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3 years ago
The law of cosine is A squared + B squared -2abcosC. find he value of 2abcosC 
Gnoma [55]
D I think but not 100% sure
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The slope of a line is 2. The y-intercept of the line is -6 Which statements accurately describe how to graph the function?
pashok25 [27]

Answer:

a

Step-by-step explanation:

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4 years ago
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If n(A) =15 n (B) = 9 n(A∩B) =4 <br> find n(A U B)
Xelga [282]

Answer:

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Step-by-step explanation:

n(A) only =15-4=11

n(B) only=9-4=5

n(A n B)=4

n(A U B)=11+5+4=20

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3 years ago
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