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Sholpan [36]
4 years ago
14

Joelle is working on a school report in a word processor. She wants to place a figure which is 13.09 \text{ cm}13.09 cm13, point

, 09, space, c, m wide so that it appears centered on the page. The width of the page is 21.59 \text{ cm}21.59 cm21, point, 59, space, c, m.
Mathematics
2 answers:
tatiyna4 years ago
7 0

Answer:

that answer is wrong the real answer is on kahn academy

Step-by-step explanation:

GuDViN [60]4 years ago
5 0
<span>Subtract 13.09 from 21.59 giving you 8.5. Since the amount of space on both the left and right margin have to be equal you would divide by 2 to get 4.25 on the left margin as well as the right.</span>
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What is the greatest common factor of 20 and 30???
Ugo [173]
The greatest common factor of 20 and 30 is 10. This is because 10 is the largest number that when it is used to divide 20 or 30, it equals a whole number.

The simple way for us to solve is to write down the factors of both numbers, find the factors that match for both numbers, and see which is the largest out of those that match.

20: <u>1</u>,<u>2</u>,4,<u>5</u>,<u>10</u>,20
30: <u>1</u>,<u>2</u>,3,<u>5</u>,6,<u>10</u>,15,30

Using that logic, we can see that 10 is the greatest factor that the numbers share.

7 0
3 years ago
Plz hurry!!!! thank you!!!!
Nikitich [7]

Answer:

Area of trapezium = 4.4132 R²

Step-by-step explanation:

Given, MNPK is a trapezoid

MN = PK and ∠NMK = 65°

OT = R.

⇒ ∠PKM = 65° and also ∠MNP = ∠KPN = x (say).

Now, sum of interior angles in a quadrilateral of 4 sides = 360°.

⇒ x + x + 65° + 65° = 360°

⇒ x = 115°.

Here, NS is a tangent to the circle and ∠NSO = 90°

consider triangle NOS;

line joining O and N bisects the angle ∠MNP

⇒ ∠ONS = \frac{115}{2} = 57.5°

Now, tan(57.5°) = \frac{OS}{SN}

⇒ 1.5697 = \frac{R}{SN}

⇒ SN = 0.637 R

⇒ NP = 2×SN = 2× 0.637 R = 1.274 R

Now, draw a line parallel to ST from N to line MK

let the intersection point be Q.

⇒ NQ = 2R

Consider triangle NQM,

tan(∠NMQ) = \frac{NQ}{QM}

⇒ tan65° = \frac{NQ}{QM}

⇒ QM = \frac{2R}{2.1445}

QM = 0.9326 R .

⇒ MT = MQ + QT

          = 0.9326 R + 0.637 R  (as QT = SN)

⇒ MT = 1.5696 R

⇒ MK = 2×MT = 2×1.5696 R = 3.1392 R

Now, area of trapezium is (sum of parallel sides/ 2)×(distance between them).

⇒ A = (\frac{NP + MK}{2}) × (ST)

       = (\frac{1.274 R + 3.1392 R}{2}) × 2 R

       = 4.4132 R²

⇒ Area of trapezium = 4.4132 R²

5 0
4 years ago
Tanya took a cab from her home to the airport. Her total fare including a tip of $5.00, was $28.50. EZ Cab Company has a pick-up
ValentinkaMS [17]
16.2 miles.

Since she paid a $5 tip, the cost for her fare was $23.50.  Let x be the number of 0.2-mile increments in the trip:
23.50 = 2.50 + 1 + 0.25(x-1)

This equation comes from the 2.50 home pick-up fee; $1 for the first 0.2-mile increment; and 0.25 for each other 0.2-mile increment.

Using the distributive property, we have:
23.50 = 2.50 + 1 + 0.25*x - 0.25*1
23.50 = 2.50 + 1 + 0.25x - 0.25

Combining like terms,
23.50 = 0.25x + 2.75

Subtracting 2.75 from both sides, we have:
23.50 - 2.75 = 0.25x + 2.75 - 2.75
20.25 = 0.25x

Dividing both sides by 0.25, we have:
20.25/0.25 = 0.25x/0.25
81 = x

This means there are 81 0.2-mile increments in her trip.  81(0.2) = 16.2 miles
6 0
4 years ago
HELP DUE in 5 mins will give 20 points
yawa3891 [41]

Answer:

B

Step-by-step explanation:

6 0
3 years ago
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At the movie theater the blaine family spent $22.00 for twoadult tickets and three child tickets. the hooper family spent $18.50
Anika [276]
2a+3c=22.00 ......equation 1
a+4c=18.50  =>2a+8c=37.00 .....equation 2
subtract equation one from equation two: 
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a+4*3=18.50 =>a=6.50

for the Hu family: 3*6.50+1*3.00=22.50 dollars
3 0
3 years ago
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