Answer:
if the bottom the RST equals 114 you judt need to subtract 114 from 72 and you get 42 :) sorry if it wrong
Step-by-step explanation:
Answer:
the answer b
Step-by-step explanation:
[surface area]=[area of 4 triangles sides]+[area of square base]
[area of square base]=24*24--------> 576 cm²
[area of one triangles side]
l=slant height
l²=16²+12²-------> l²=400-----------> l=20 cm
[area of one triangles side]=24*20/2--------> 240 cm²
[area of 4 triangles sides]=4*240----------> 960 cm²
[surface area]=[960]+[576]--------> 1536 cm²
A = 84.825 because the area of a circle is 113.1 and 1/4 of it is missing.
I think that the best answer here would be that A = 40 degrees.
Let's let the weight of a large box be L, and the weight of a small box be S.
We know that 5 large boxes and 3 small boxes is 120kg, so:
5L + 3S = 120
We also know that 7 large boxes and 9 small boxes is 234kg, so:
7L + 9S = 234
You can multiply the first equation by 3 to get:
15L + 9S = 360
See how now both equations have 9S? We can now subtract one from the other:
(15L+9S) - (7L+9S) = 360-234
8L = 126
L = 15.75
Now sub this value back into an equation:
(5x15.75) + 3S = 120
3S = 41.25
S = 13.75
Double check these values
(7x15.75) + (9x13.75)
= 110.25 + 123.75
=234, which is consistent with above.
So a large box is 15.75kg, and a small box is 13.75kg.
Hope this helped
