All categories

2 years ago

The product of 5 and a number n is at least 25.

Mathematics

1 answer:

Afina-wow [57]2 years ago

3 0

5x2+15=25 is the answer

You might be interested in

Determine whether the underlined value is a parameter or a statistic. One of the greatest baseball hitters of all time has a car

Ad libitum [116K]

Answer:

B. The value is a parameter because the career at-bats of a baseball player are a population.

Step-by-step explanation:

The hitter had a career batting average of 0.366.

This value comes from information about the population of every time he has ever gone up to bat. Therefore, it is a parameter.

If on the other hand, we take the batting average of 5 games, the 5 games will be a sample and the batting average will be a statistic.

5 0

2 years ago

Subtract. Express your answer in lowest terms. 10 5/11 - 4 2/11

Zigmanuir [339]

Answer:

6 3 /11

Step-by-step explanation:

10 5/11 - 4 2/11

since they already have a common denominator

10 5/ 11

- 4 2 /11

-------------

6 3 /11

6 0

3 years ago

Read 2 more answers

Jade buys a blouse and a skirt for 3/6 of their original price. Jade pays a total of $31 for the two items. If the original pric

Damm [24]

Answer:

3/4 times 18= 13.5

31.5-13.5=18

It cost 18 dollars for the skirt with a discount.

It cost 13.5 for the blouse as opposed to the original price of 18 dollars.

18(skirt)+13.5(blouse)=31.5

If you set up a proportion to find the original price of the skirt you will get the answer.

18/x=75/100

75x=18 times 100

75x=1800

75x/75=1800/75

x=24

The original price of the skirt is 24 dollars.

Step-by-step explanation:

4 0

2 years ago

Find the laplace transform of f(t) = cosh kt = (e kt + e −kt)/2

iren2701 [21]

Hello there, hope I can help!

I assume you mean $L\left\{\frac{ekt+e-kt}{2}\right\}$
With that, let's begin

$\frac{ekt+e-kt}{2}=\frac{ekt}{2}+\frac{e}{2}-\frac{kt}{2} \ \textgreater \ L\left\{\frac{ekt}{2}-\frac{kt}{2}+\frac{e}{2}\right\}$

$\mathrm{Use\:the\:linearity\:property\:of\:Laplace\:Transform}$
$\mathrm{For\:functions\:}f\left(t\right),\:g\left(t\right)\mathrm{\:and\:constants\:}a,\:b$
$L\left\{a\cdot f\left(t\right)+b\cdot g\left(t\right)\right\}=a\cdot L\left\{f\left(t\right)\right\}+b\cdot L\left\{g\left(t\right)\right\}$
$\frac{ek}{2}L\left\{t\right\}+L\left\{\frac{e}{2}\right\}-\frac{k}{2}L\left\{t\right\}$

$L\left\{t\right\} \ \textgreater \ \mathrm{Use\:Laplace\:Transform\:table}: \:L\left\{t\right\}=\frac{1}{s^2} \ \textgreater \ L\left\{t\right\}=\frac{1}{s^2}$

$L\left\{\frac{e}{2}\right\} \ \textgreater \ \mathrm{Use\:Laplace\:Transform\:table}: \:L\left\{a\right\}=\frac{a}{s} \ \textgreater \ L\left\{\frac{e}{2}\right\}=\frac{\frac{e}{2}}{s} \ \textgreater \ \frac{e}{2s}$

$\frac{ek}{2}\cdot \frac{1}{s^2}+\frac{e}{2s}-\frac{k}{2}\cdot \frac{1}{s^2}$

$\frac{ek}{2}\cdot \frac{1}{s^2} \ \textgreater \ \mathrm{Multiply\:fractions}: \frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d} \ \textgreater \ \frac{ek\cdot \:1}{2s^2} \ \textgreater \ \mathrm{Apply\:rule}\:1\cdot \:a=a$
$\frac{ek}{2s^2}$

$\frac{k}{2}\cdot \frac{1}{s^2} \ \textgreater \ \mathrm{Multiply\:fractions}: \frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d} \ \textgreater \ \frac{k\cdot \:1}{2s^2} \ \textgreater \ \mathrm{Apply\:rule}\:1\cdot \:a=a$
$\frac{k}{2s^2}$

$\frac{ek}{2s^2}+\frac{e}{2s}-\frac{k}{2s^2}$

Hope this helps!

3 0

2 years ago

Buyers are skeptical of a motorcycle advertisement that claims the newest model gets an average of 52 miles per gallon. They bel

Lana71 [14]

Answer:

Null hypothesis; H0: µ ≥ 52 mpg

Alternative hypothesis; Ha: µ < 52 mpg

Step-by-step explanation:

We are told that the newest model gets an average of 52 miles per gallon and that the buyers believe that the average mpg was overstated.

This means the alternative hypothesis will have an average less than 52. Thus;

Null hypothesis; H0: µ ≥ 52 mpg

Alternative hypothesis; Ha: µ < 52 mpg

3 0

2 years ago