All categories

3 years ago

The product of 5 and a number n is at least 25.

Mathematics

1 answer:

Afina-wow [57]3 years ago

3 0

5x2+15=25 is the answer

You might be interested in

the parking garage holds 300 cars on each level. There are 4 levels in the garage. How many cars can the parking garage hold in

nikklg [1K]

300*4. 1200 in total

3 0

3 years ago

Read 2 more answers

Explain whether the product of an even number x odd number x odd number is even or odd?

Dmitriy789 [7]

Well an example is 4x3x3 which equals 36 which is even

3 0

3 years ago

Read 2 more answers

Marta can vacuum the house in 30 min. It takes her daughter 45 min to vacuum the house. How long would it take them if they

Mamont248 [21]

Answer:

Step-by-step explanation:

This problem is on combined work rate

given that

Marta can vacuum the house in 30 min

then her rate= 1/30

Also, her daughter will take 45 min to vacuum the house

her daughter's rate will be = 1/45

then the combined work rate is

1/30+1/45=1/T

30+45/30*45=1/T

75/1350= 1/T

1/18=1/T

This means that they will both take 18 minutes working together to vacum a house

8 0

2 years ago

Help if you can -

yulyashka [42]

Answer:

1.875 commercials a minute

Step-by-step explanation:

4 0

2 years ago

A particular isotope has a half-life of 74 days. If you start with 1 kilogram of this isotope, how much will remain after 150

shtirl [24]

$\bf \stackrel{150~days}{\textit{Amount for Exponential Decay using Half-Life}} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &1\\ t=\textit{elapsed time}\dotfill &150\\ h=\textit{half-life}\dotfill &74 \end{cases} \\\\\\ A=1\left( \frac{1}{2} \right)^{\frac{150}{74}}\implies A=1\left( \frac{1}{2} \right)^{\frac{75}{37}}\implies \boxed{A\approx 0.24536}$

$\bf \stackrel{300~days}{\textit{Amount for Exponential Decay using Half-Life}} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &1\\ t=\textit{elapsed time}\dotfill &300\\ h=\textit{half-life}\dotfill &74 \end{cases} \\\\\\ A=1\left( \frac{1}{2} \right)^{\frac{300}{74}}\implies A=1\left( \frac{1}{2} \right)^{\frac{150}{37}}\implies \boxed{A\approx 0.060202}$

6 0

3 years ago