Answer:
correlation can be used to determine the direction of the relationship between two variables may be this is the answer not sure
True
A linear recurrence relation involving a sequence of numbers
is one of the form
![\displaystyle\sum_{k=0}^nc_{n-k}a_{n-k}=c_na_n+c_{n-1}a_{n-1}+\cdots+c_2a_2+c_1a_1=c](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Csum_%7Bk%3D0%7D%5Enc_%7Bn-k%7Da_%7Bn-k%7D%3Dc_na_n%2Bc_%7Bn-1%7Da_%7Bn-1%7D%2B%5Ccdots%2Bc_2a_2%2Bc_1a_1%3Dc)
where
and
are any fixed numbers.
The given recurrence can be rearranged as
![a_n=a_{n-1}+2\implies 1\cdot a_n+(-1)\cdot a_{n-1}=2](https://tex.z-dn.net/?f=a_n%3Da_%7Bn-1%7D%2B2%5Cimplies%201%5Ccdot%20a_n%2B%28-1%29%5Ccdot%20a_%7Bn-1%7D%3D2)
A nonlinear recurrence would have a more "exotic" form that cannot be written in the form above. Some example:
![a_n+\dfrac1{a_{n-1}}=1](https://tex.z-dn.net/?f=a_n%2B%5Cdfrac1%7Ba_%7Bn-1%7D%7D%3D1)
![a_na_{n-1}=\pi](https://tex.z-dn.net/?f=a_na_%7Bn-1%7D%3D%5Cpi)
![{a_n}^2+\sqrt{a_{n-1}}-\left(\dfrac{a_{n-2}}{\sqrt{a_n}}\right)^{a_{n-3}}=0](https://tex.z-dn.net/?f=%7Ba_n%7D%5E2%2B%5Csqrt%7Ba_%7Bn-1%7D%7D-%5Cleft%28%5Cdfrac%7Ba_%7Bn-2%7D%7D%7B%5Csqrt%7Ba_n%7D%7D%5Cright%29%5E%7Ba_%7Bn-3%7D%7D%3D0)
Answer:
314.2
Step-by-step explanation:
area = pi times radius to the second power
10 times 10 = 100
100 times 3.142 = 314.2
Answer:
1*(9+7):(2+6)*1=2
Step-by-step explanation:
Answer:
23
Step-by-step explanation:
if you want the steps lmk in the comments (not everyone wants them). hope this helps Happy Holidays