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ratelena [41]
4 years ago
5

Last one ... (w+6)^2=3(w+12)-w^2

Mathematics
1 answer:
wariber [46]4 years ago
3 0
First, distribute on both sides.
w^2+6^2=3w+36-w^2
Simplify 6^2.
w^2+36=3w+36-w^2
Subtract w^2 from both sides.
36=3w+36
Subtract 36 from both sides.
0=3w
Divide both sides by 3.
0=w
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Answer:

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Step-by-step explanation:

Its domain is the only one of these that contain -2, which is a real number.

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Answer:

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water in a canal , 6m wide and 1.5m deep , flowing with a speed of 10km/h . How much area will it irrigate in 30 minutes , if 8
icang [17]

The area covered by the canal in 30 mins is 562500 sq m

Step-by-step explanation:

Step 1 :

Given,

The canal's width = 6 meter

The canal's Depth is given as 1.5 meter

Speed of the water flowing = 10 kilometer per hour  

We need to determine the area which will be irrigated in 30 mins

Step 2 :

In one hour the canal flows 10 kilometer , therefore in 30 minutes it covers 5 kilometer = 5 × 10^{(3)} meter

Hence the volume of the water irrigated per 30 minutes = 6 × 1.5 × 5 × 10^{(3)}

= 45 × 10^{(3)}   cubic meter

The standing water is 8 centimeter = 8 × 10^{(-2)}  meter

Hence the area covered in 30 min = Volume ÷ the height of the standing water

= (45 × 10^{(3)} )  ÷ 8 × 10^{(-2)}   meter

= 562500 square meter

Step 3 :

The area covered by the canal in 30 mins is 562500 square meter

4 0
3 years ago
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