3x - 5y = 7
2x + 3y = 11
multiply the first equation by 2 and the second by -3:-
6x - 10y = 14
-6x - 9y = -33 Adding these 2 equations we eliminate the term in x:-
-19y = -19
y = 1
Substtute y = 1 in the first equation:_
3x - 5(1) = 7
3x = 12
x = 4
Answer is x=4,y=1 Answer
Second system of equation:-s
Here one equation is linear and the other is quadratic so we substitute fro y in the quadratic:-
From second equation y = 10x - 38, so substituting:-
10x - 38 = x^2 - 4x - 17
Gotta go right now . Sorry
Answer:
5 rectangles
Step-by-step explanation:
got it right on edg
Answer:
29,31
Step-by-step explanation:
Answer:
25,31,37
Step-by-step explanation:
n should be positive integer number. The three numbers in both sequences have different term number n but same value. We can equalize each nth term in the question to "a" which represents one of the three numbers.
a=2n-1, then n=(a+1)/2
a=3n+1, then n=(a-1)/3
remember the two n above are different but both should be positive integer. That means, we have to find the "a" number that gives me an integer n for the first equation. The possible numbers between 20 to 40 are 22,25,28,31,34,37,40.
The possible numbers for the second equation are 21,23,25,27,29,31,33,35,37,39.
Now find the common numbers between the two sets above. They are 25,31,37
The answer is -12
these are the steps on how to find that
-2x2y
-2(-3)2(y)
6 times -2
-12
