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liubo4ka [24]
3 years ago
9

A cybersecurity analyst is currently investigating a server outage. The analyst has discovered the following value was entered f

or the username: 0xbfff601a. Which of the following attacks may be occurring?
(A) Buffer overflow attack
(B) Man-in-the-middle attack
(C) Smurf attack
(D) Format string attack
(E) Denial of service attack
Computers and Technology
1 answer:
drek231 [11]3 years ago
8 0

Answer:D)Format string attack

Explanation:

Format string attack is the type of attack that causes to change the application functioning .This attack access the memory of the string library. It occurs while the submission of the string as input and then gets tested due to application command.

Other options are incorrect because these are the attacks that don't happens in the application for the alteration of the flow. Thus, the correct option is option(D).

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What would you have to know about the pivot columns in an augmented matrix in order to know that the linear system is consistent
Scrat [10]

Answer:

The Rouché-Capelli Theorem. This theorem establishes a connection between how a linear system behaves and the ranks of its coefficient matrix (A) and its counterpart the augmented matrix.

rank(A)=rank\left ( \left [ A|B \right ] \right )\:and\:n=rank(A)

Then satisfying this theorem the system is consistent and has one single solution.

Explanation:

1) To answer that, you should have to know The Rouché-Capelli Theorem. This theorem establishes a connection between how a linear system behaves and the ranks of its coefficient matrix (A) and its counterpart the augmented matrix.

rank(A)=rank\left ( \left [ A|B \right ] \right )\:and\:n=rank(A)

rank(A)

Then the system is consistent and has a unique solution.

<em>E.g.</em>

\left\{\begin{matrix}x-3y-2z=6 \\ 2x-4y-3z=8 \\ -3x+6y+8z=-5  \end{matrix}\right.

2) Writing it as Linear system

A=\begin{pmatrix}1 & -3 &-2 \\  2& -4 &-3 \\ -3 &6  &8 \end{pmatrix} B=\begin{pmatrix}6\\ 8\\ 5\end{pmatrix}

rank(A) =\left(\begin{matrix}7 & 0 & 0 \\0 & 7 & 0 \\0 & 0 & 7\end{matrix}\right)=3

3) The Rank (A) is 3 found through Gauss elimination

(A|B)=\begin{pmatrix}1 & -3 &-2  &6 \\  2& -4 &-3  &8 \\  -3&6  &8  &-5 \end{pmatrix}

rank(A|B)=\left(\begin{matrix}1 & -3 & -2 \\0 & 2 & 1 \\0 & 0 & \frac{7}{2}\end{matrix}\right)=3

4) The rank of (A|B) is also equal to 3, found through Gauss elimination:

So this linear system is consistent and has a unique solution.

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