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ZanzabumX [31]
3 years ago
12

The ideal width of a safety belt strap for a certain automobile is 5 cm. An actual width can vary by at most 0.35 cm. Write and

solve an absolute value inequality for the range of acceptable widths.
Mathematics
1 answer:
notsponge [240]3 years ago
8 0

Answer:

4.65\leq x\leq 5.35

Step-by-step explanation:

Let the actual width of belt be x

we are given that the ideal width of safety belt strap is 5 cm

So, Difference between actual and ideal = (x-5)cm

We are also given that An actual width can vary by at most 0.35 cm.

So, The difference between actual and ideal width should be less than or equal to 0.35 cm

So, |x-5|\leq 0.35

We know

x-5\leq 0.35 and x-5\geq -0.35

x\leq 0.35+5 and x\geq -0.35+5

x\leq 5.35 and x\geq 4.65

So, 4.65\leq x\leq 5.35

Hence the range of acceptable widths is 4.65\leq x\leq 5.35

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Answer:

48p^2+2p-4

Step-by-step explanation:

We can use the FOIL method to expand two multiplied binomials. It states that (a+b)(c+d)=ac+bc+ac+bd. The FOIL method stands for First(first terms) outer(outer terms) inner(inner terms) last(last terms).

So, we can expand our binomials now!

(8p-2)(6p+2)=(8p)(6p)-2(6p)+(8p)(2)-2(2)=48p^2-12p+14p-4=\boxed{48p^2+2p-4}

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Answer:

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Step-by-step explanation:

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Step 1 of 1

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