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3 years ago

when reading Shakespeare what is not an important reason fpr utilizing strategies such as paraphrasing and summarizing

1 answer:

4 0

In reading Shakespeare's collection of works, it is very necessary to learn how to paraphrase or summarize in order to understand his writings. One of the not-so-important reasons that needs the least consideration in utilizing strategies such as paraphrasing and summarizing could be the fear to change the real and original taste or meaning of the writings.

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Fernando evaluated the expression below. StartFraction 5 (9 minus 5) over 2 EndFraction + (negative 2) (negative 5) + (negative

Juli2301 [7.4K]

Question:

Fernando evaluated the expression below.

$\frac{5(9-5)}{2} + (-2)(-5) + (-3)^2 = \frac{5(4)}{2} -10 + 9 = \frac{20}{2} - 10 + 9 = 10 - 10 + 9 = 9$

What was Fernando's error?

- Fernando evaluated the numerator of the fraction incorrectly.

- Fernando simplified 20/2 incorrectly.

- Fernando incorrectly found the product of –2 and –5.

- Fernando evaluated (-3)² incorrectly.

Answer:

- Fernando incorrectly found the product of –2 and –5.

Explanation:

Given

$\frac{5(9-5)}{2} + (-2)(-5) + (-3)^2 = \frac{5(4)}{2} -10 + 9 = \frac{20}{2} - 10 + 9 = 10 - 10 + 9 = 9$

Required

Spot the error

The error in this evaluation is the product of -2 and -5 at step 2

When a negative number (-2) is multiplied by a negative number (-5), the outcome of the multiplication is always a positive number (10).

So, the result of -2 * -5 is 10 but Fernando incorrectly calculated it as -10.

Solving the expression, correctly

$\frac{5(9-5)}{2} + (-2)(-5) + (-3)^2 = \frac{5(4)}{2} + 10 + 9$

$\frac{5(9-5)}{2} + (-2)(-5) + (-3)^2 = \frac{20}{2} + 10 + 9$

$\frac{5(9-5)}{2} + (-2)(-5) + (-3)^2 = 10 + 10 + 9$

$\frac{5(9-5)}{2} + (-2)(-5) + (-3)^2 = 29$

Hence, the actual result of the expression is 29 (not 9 as calculated by Fernando).

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