Answer:
- the pressure will decrease
(volume is doubled ,the pressure reduced by half).
Step-by-step explanation:
P_1 V_1=P_2 V_2
This equation shows that, as volume increases, the pressure of the gas decreases in proportion.
Similarly, as volume decreases, the pressure of the gas increases.
2. 653.5 m^3
3. 706.9 m^3
4. 141.4 m^3
5. 2309.1 m^3
6. 402.1 m^3
7. 1900.1 m^3
8. 2001.2 m^3
9. 461.8 m^3
Answer:
0.19
Step-by-step explanation:
There are approximately .62 miles in a kilometer
Hey Jinx :)
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Note that a decay has a rate between 0 and 1, and a growth as a rate of 1 or higher.
y = 1/2(1 + 0.03)^t → y = 1/2(1.03)^t (Rate is more then 0) GROWTH
y = 0.3(0.95)^t → (Rate is between 0 and 1) DECAY
y = ((1+0.03)^1/2)^2t → y = y = 1.014^2t (Rate is more then 0) GROWTH
y = 200(0.73)^t → (Rate is between 0 and 1) DECAY
y = 4(1/4)^t → (Rate is between 0 and 1) DECAY
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Hope This Helped! Good Luck!
A stuntman jumping off a 20-m-high building is modeled by the equation h = 20 – 5t2, where t is the time in seconds. A high-speed camera is ready to film him between 15 m and 10 m above the ground. For which interval of time should the camera film him?
Answer:
Step-by-step explanation:
Given:
A stuntman jumping off a 20-m-high building is modeled by the equation
-----------(1)
A high-speed camera is ready to making film between 15 m and 10 m above the ground
when the stuntman is 15m above the ground.
height 
Put height value in equation 1
We know that the time is always positive, therefore 
when the stuntman is 10m above the ground.
height 
Put height value in equation 1
Therefore ,time interval of camera film him is
