Question

A: What are the solutions to the quadratic equation?

Answer 1

Answer:

A. x = -1 or x = 3

B. first

Step-by-step explanation:

$x^2-2x-3=0\\\\x^2+x-3x-3=0\\\\x(x+1)-3(x+1)=0\\\\(x+1)(x-3)=0\iff x+1=0\ \vee\ x-3=0\\\\x+1=0\qquad\text{subtract 1 from both sides}\\x=-1\\\\x-3=0\qquad\text{add 3 to both sides}\\x=3$