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3 years ago

Which statement is TRUE about 300?

Mathematics

1 answer:

BigorU [14]3 years ago

7 0

Answer

the answer is D

Step-by-step explanation:

the square root of 300 is 17.3

so there for it lies between 17 and 18

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Write a polynomial Of least degree With roots zero and -3

GuDViN [60]

Answer:

X^2+3x

Step-by-step explanation:

in order to get these roots, we would set up the equation to be (x)(x+3). We can then multiply it to get x^2+3x

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3 years ago

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Ivanshal [37]

Answer:

Answer should be choice 4

Step-by-step explanation:

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3 years ago

How do I find this this answer?

Viefleur [7K]

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3 years ago

Read 2 more answers

Camden is taking a multiple choice test with a total of 50 points available. Each question is worth exactly 5 points. What would

alina1380 [7]

Answer:

<h2>1. 40 points</h2><h2>2. 50-x points </h2>

Step-by-step explanation:

1. Given that the total number of points is 50

2. Each question is worth 5 points

We can now calculate the number of questions by dividing the total points by the worth of each question

the number of question is = 50/5= 10

hence there are 10 questions available

if he misses 2 questions, which will amount to 10 points his score will be

50-10 = 40 points

Hence if he got x questions wrong his score will be

50-x points

8 0

3 years ago

let sin(θ) =3/5 and tan(y) =12/5 both angels comes from 2 different right trianglesa)find the third side of the two tringles b)

statuscvo [17]

In a right triangle, we haev some trigonometric relationships between the sides and angles. Given an angle, the ratio between the opposite side to the angle by the hypotenuse is the sine of this angle, therefore, the following statement

$\sin (\theta)=\frac{3}{5}$

Describes the following triangle

To find the missing length x, we could use the Pythagorean Theorem. The sum of the squares of the legs is equal to the square of the hypotenuse. From this, we have the following equation

$x^2+3^2=5^2$

Solving for x, we have

$\begin{gathered} x^2+3^2=5^2 \\ x^2+9=25 \\ x^2=25-9 \\ x^2=16 \\ x=\sqrt[]{16} \\ x=4 \end{gathered}$

The missing length of the first triangle is equal to 4.

For the other triangle, instead of a sine we have a tangent relation. Given an angle in a right triangle, its tanget is equal to the ratio between the opposite side and adjacent side.The following expression

$\tan (y)=\frac{12}{5}$

Describes the following triangle

Using the Pythagorean Theorem again, we have

$5^2+12^2=h^2$

Solving for h, we have

$\begin{gathered} 5^2+12^2=h^2 \\ 25+144=h^2 \\ 169=h^2 \\ h=\sqrt[]{169} \\ h=13 \end{gathered}$

The missing side measure is equal to 13.

Now that we have all sides of both triangles, we can construct any trigonometric relation for those angles.

The sine is the ratio between the opposite side and the hypotenuse, and the cosine is the ratio between the adjacent side and the hypotenuse, therefore, we have the following relations for our angles

$\begin{gathered} \sin (\theta)=\frac{3}{5} \\ \cos (\theta)=\frac{4}{5} \\ \sin (y)=\frac{12}{13} \\ \cos (y)=\frac{5}{13} \end{gathered}$

To calculate the sine and cosine of the sum

$\begin{gathered} \sin (\theta+y) \\ \cos (\theta+y) \end{gathered}$

We can use the following identities

$\begin{gathered} \sin (A+B)=\sin A\cos B+\cos A\sin B \\ \cos (A+B)=\cos A\cos B-\sin A\sin B \end{gathered}$

Using those identities in our problem, we're going to have

$\begin{gathered} \sin (\theta+y)=\sin \theta\cos y+\cos \theta\sin y=\frac{3}{5}\cdot\frac{5}{13}+\frac{4}{5}\cdot\frac{12}{13}=\frac{63}{65} \\ \cos (\theta+y)=\cos \theta\cos y-\sin \theta\sin y=\frac{4}{5}\cdot\frac{5}{13}-\frac{3}{5}\cdot\frac{12}{13}=-\frac{16}{65} \end{gathered}$

4 0

1 year ago