Question

Find the (a) mean, (b) median, (c) mode, and (d) midrange for the data and then (e) answer the given question. Listed below are the amounts (dollars) it costs for marriage proposal packages at different sports venues. Are there any outliers? 39 50 50 55 55 55 65 85 100 125 175 175 200 209 250 250 325 400 425 500 500 500 500 1500 2500

Answer 1

Answer:

Step-by-step explanation:

(a) Mean = (39+50+50+55+55+55+65+85+100+125+175+175+200+

209+250+250+325+400+425+500+500+500+500+1500+2500) ÷ (25)

               = (9088) ÷ (25)

              = 363.52

The mean of the data is 363.52

(b) Given: 39, 50, 50, 55, 55, 55, 65, 85, 100, 125, 175, 175, 200, 209, 250, 250, 325, 400, 425, 500, 500, 500, 500, 1500, 2500.

the median value is 200.

(c) The mode is the value with highest frequency. The mode is 500.

(d)  Mid range = $\frac{39+2500}{2}$

                      = 1269.5

An outlier is a value that is significantly different from other values in the data, thus affects the mean considerably. Yes, 2500 is the outlier.