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Snezhnost [94]
3 years ago
6

Write a two digit number greater than 40 that is divisible by 2 and 3​

Mathematics
2 answers:
USPshnik [31]3 years ago
8 0

Answer:

42

Step-by-step explanation:

bigger than 40.  Divisible by 2 (any even number).  

Kamila [148]3 years ago
8 0

Answer:

42, 44, 46, 48, 50, 52, 54, 56, 58, 60, 62, 64, 66, 68, 70, 72, 74, 76, 78, 80, 82, 84, 86, 88, 90, 92, 94, 96, 98

Step-by-step explanation:

We can tell if 2 divides into this number without a remainder by just looking at the last digit. 456,791,824 - the last digit is a 4. This means that the number is EVEN and 2 will divide into it

if the sum of the digits of a number is divisible by 3, then the number is divisible by 3. to quickly find a factor of 621 other than 1 and itself. The sum of the digits of 621 is 6+2+1 = 9.

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What does it mean to draw and label a line a line segment a ray and an angle
AVprozaik [17]

Answer:

A line in geometry is a straight line that goes on infinitely in two directions. To draw a line, you would draw a straight line and add two small arrows on both ends to indicate that they stretch infinitely. To label a line, you would either label two points on the line, or you can assign a letter to the line. (Example: ↔AB or line A)

A line segment is similar to a line, but it doesn't go infinitely in either direction. To draw a line segment, you would draw two points and connect them. To label a line segment, you would label the two endpoints. (Example: ¯AB)

A ray is a line with one side that extends infinitely. To draw a ray, you would draw a point, draw a line from the point going in any direction, and add an arrow on the other end to indicate that it extends forever. To label a ray, you would label the endpoint and some other point on the ray. (Example: →AB)

An angle is the shape formed by two rays that have a common endpoint. To draw an angle, you would draw an endpoint and make two separate rays coming off of it. Then you would draw a short arc in the space between the rays to indicate that it is an angle. There are three ways to label an angle:

1. Label the vertex (∠A)

2. Label a point on one ray, the endpoint, then a point on the other ray (∠BAC)

3. Label the angle with a number or letter (∠1, ∠A)

8 0
3 years ago
Find the sine of ∠W.
DedPeter [7]

Answer:

sin(w) =  \frac{30}{34}  \\ sin(w) =  \frac{15}{17}

3 0
2 years ago
Complete the equation describing how x and y are related
Leya [2.2K]

Answer:

y= x + 6

Step-by-step explanation

you need to add 6 to the input to get the output

3 0
3 years ago
Write the equation of the quadratic function that passes through the points (-1, 1), (1, 5), and (2,10).
Serjik [45]

Answer:

\displaystyle f(x)=x^2+2x+2

Step-by-step explanation:

<u>System Of Linear Equations </u>

In this problem, we'll need to solve a 3x3 system of linear equations because we have three unknowns and three conditions.

We are required to find the equation of the quadratic function that passes through the points (-1, 1), (1, 5), and (2,10)

The general quadratic function can be written as

\displaystyle f(x)=ax^2+bx+c

We need to find the values of a,b, and c. Let's use the first condition, i.e. f(-1)=1

\displaystyle f(-1)=a(-1)^2+b(-1)+c

\displaystyle f(-1)=a-b+c

\displaystyle a-b+c=1.....[eq\ 1]

Now we use the second condition f(1)=5

\displaystyle f(1)=a(1)^2+b(1)+c

\displaystyle f(1)=a+b+c

\displaystyle a+b+c=5.......[eq\ 2]

Finally, we use the third condition f(2)=10

\displaystyle f(2)=a(2)^2+b(2)+c

\displaystyle f(2)=4a+2b+c

\displaystyle 4a+2b+c=10....[eq\ 3]

We put together eq 1, eq 2, and eq 3 to form the system

\displaystyle \left\{\begin{matrix}a-b+c=1\\ a+b+c=5\\ 4a+2b+c=10\end{matrix}\right.

Adding the first two equations we have

\displaystyle 2a+2c=6

\displaystyle a+c=3

And also

\displaystyle b=2

Using the above equation and the value of b in the third equation, we have

\displaystyle \left\{\begin{matrix}a+c=3\\ 4a+c=6\end{matrix}\right.

Subtracting the first equation from the second

\displaystyle 3a=3

\displaystyle a=1

And therefore

\displaystyle c=2

Now we have all the values, the quadratic function is

\displaystyle \boxed{f(x)=x^2+2x+2}

6 0
3 years ago
PLEASEE HELP ANYONE WHO IS GOOD AT MATH
Lorico [155]
\sqrt{\frac{126xy^{5}}{32x^{3}}}=\sqrt{\frac{63y^{5}}{ax^{b}}}\\\\\sqrt{\frac{63y^{5}}{16x^{2}}}=\sqrt{\frac{63y^{5}}{ax^{b}}}\\\\\frac{\sqrt{63y^{5}}}{\sqrt{16x^{2}}}=\frac{\sqrt{63y^{5}}}{\sqrt{ax^{b}}}\\\\\frac{\sqrt{63y^{5}}}{\sqrt{16x^{2}}}*\frac{1}{\sqrt{63y^{5}}}=\frac{\sqrt{63y^{5}}}{\sqrt{ax^{b}}}*\frac{1}{\sqrt{63y^{5}}}\\\\\frac{1}{\sqrt{16x^{2}}}=\frac{1}{\sqrt{ax^{b}}}\\\\\sqrt{16x^{2}}=\sqrt{ax^{b}}

Thus for the two equations to be equal, a = 16 and b = 2.
8 0
3 years ago
Read 2 more answers
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