3 + 2 = 5
5 + 4 = 9
9 + 68 = 77
77 + 6974 = 7051
7051 + 87643 = 94694
94694 + 8654 = 103348
Total kicks that were attempted = 40
Goals blocked by Kyra = 55%;
Goals which could not be blocked by Kyra = 100 - 55 = 45%
Goals made during team drill = 18
Let total kicks attempted be 'n';
Therefore;
(18/n) × 100 % = 45 %
18/n = 45/100;
n = 1800/45;
n = 40
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Answer:
no writting shown but
Step-by-step explanation:
i guess its super cool encouragement is the most
1st problem:
A = 630 cm
2nd problem:
A = 104 cm
All I can see on the picture you provided.
Answer:
A.) gf(x) = 3x^2 + 12x + 9
B.) g'(x) = 2
Step-by-step explanation:
A.) The two given functions are:
f(x) = (x + 2)^2 and g(x) = 3(x - 1)
Open the bracket of the two functions
f(x) = (x + 2)^2
f(x) = x^2 + 2x + 2x + 4
f(x) = x^2 + 4x + 4
and
g(x) = 3(x - 1)
g(x) = 3x - 3
To find gf(x), substitute f(x) for x in g(x)
gf(x) = 3( x^2 + 4x + 4 ) - 3
gf(x) = 3x^2 + 12x + 12 - 3
gf(x) = 3x^2 + 12x + 9
Where
a = 3, b = 12, c = 9
B.) To find g '(12), you must first find the inverse function of g(x) that is g'(x)
To find g'(x), let g(x) be equal to y. Then, interchange y and x for each other and make y the subject of formula
Y = 3x + 3
X = 3y + 3
Make y the subject of formula
3y = x - 3
Y = x/3 - 3/3
Y = x/3 - 1
Therefore, g'(x) = x/3 - 1
For g'(12), substitute 12 for x in g' (x)
g'(x) = 12/4 - 1
g'(x) = 3 - 1
g'(x) = 2.
