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3 years ago

Which two sentences explain the North's opposition to the use of slavery in the South?

History

2 answers:

Sergio [31]3 years ago

8 0

Answer:

Northerners saw slavery as an immoral and unjust practice.
Northern farmers couldn't compete with Southern plantations supported by slave labor.

Explanation:

The practice of slavery was very cruel and the slaves were treated horrifically.
There were many slaves working the Southern plantations, and they gained more wealth because the plantation owners didn't pay the workers.

notsponge [240]3 years ago

3 0

Answer:

The actual answer is

Northerners saw slavery as an immoral and unjust practice.

Northern farmers couldn't compete with Southern plantations supported by slave labor.

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Various monuments constructed in pakistan show their grandeur but nowadays they are being affected by many external factors. Ide

Vikentia [17]

Answer:

Various external factors such as air pollution, acid rain, development, tourism, and ineffective policies are affecting the monuments.

Explanation:

Sulfur dioxide gases have polluted the air. They fall on the marble stone of the monuments in the form of acid rain. A corrosive reaction takes place, and it dissolves the marble and damages it badly. Other than this, the construction of new buildings around the monuments is also affecting cultural heritage.

4 0

3 years ago

(x+1/x-1 - x-1/x+1 - 4x/x^2 +1) + 4x/x^4-1

Lunna [17]

Answer:

$\frac{12x}{x^4-1}$

Explanation:

Given

$(\frac{x+1}{x-1} - \frac{x-1}{x+1} - \frac{4x}{x^2 + 1}) + \frac{4x}{x^4 - 1}$

Required

Solve:

Take L.C.M of the first two fractions

$(\frac{(x+1)(x+1)-(x-1)(x-1)}{(x-1)(x+1)} - \frac{4x}{x^2 + 1}) + \frac{4x}{x^4 - 1}$

$(\frac{(x+1)(x+1)-(x-1)(x-1)}{x^2-1} - \frac{4x}{x^2 + 1}) + \frac{4x}{x^4 - 1}$

$(\frac{x^2+2x+1-(x^2-2x+1)}{x^2-1} - \frac{4x}{x^2 + 1}) + \frac{4x}{x^4 - 1}$

$(\frac{x^2+2x+1-x^2+2x-1}{x^2-1} - \frac{4x}{x^2 + 1}) + \frac{4x}{x^4 - 1}$

Collect Like Terms

$(\frac{x^2-x^2+2x+2x+1-1}{x^2-1} - \frac{4x}{x^2 + 1}) + \frac{4x}{x^4 - 1}$

$(\frac{4x}{x^2-1} - \frac{4x}{x^2 + 1}) + \frac{4x}{x^4 - 1}$

Solve the expression in bracket

$(\frac{4x(x^2+1) - 4x(x^2-1)}{(x^2-1)(x^2+1)} ) + \frac{4x}{x^4 - 1}$

$(\frac{4x(x^2+1) - 4x(x^2-1)}{x^4-1} ) + \frac{4x}{x^4 - 1}$

$(\frac{4x^3+4x - 4x^3+4x)}{x^4-1} ) + \frac{4x}{x^4 - 1}$

$(\frac{4x^3- 4x^3+4x +4x)}{x^4-1} ) + \frac{4x}{x^4 - 1}$

$\frac{8x}{x^4-1} + \frac{4x}{x^4 - 1}$

Take LCM

$\frac{8x+4x}{x^4-1}$

$\frac{12x}{x^4-1}$

<em>The expression can not be further simplified</em>

7 0

3 years ago

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STALIN [3.7K]

Answer:

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Explanation:

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3 years ago

True [87]

Answer:

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Explanation:

5 0

3 years ago

5. Which was NOT a reason for taking slaves.

Wittaler [7]

Answer: its 3 cuz they never helped learn english

Explanation:

5 0

3 years ago

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