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Daniel [21]
3 years ago
11

What is 3y+14-2=0 in substitution

Mathematics
1 answer:
Nataly_w [17]3 years ago
5 0

Answer:

y=-4

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

3y+14−2=0

3y+14+(−2)=0

(3y)+(14+(−2))=0 (Combine Like Terms)

3y+12=0

3y+12=0

Step 2: Subtract 12 from both sides.

3y+12−12=0−12

3y=−12

Step 3: Divide both sides by 3.

3y/3= −12/3

y=−4

Answer:

y=−4

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