Answer: -3.2b + 9
Step-by-step explanation:
1. Remove parentheses.
-6.5b + 11 + 3.3b - 2
2. Add -6.5b and 3.3b.
-3.2b + 11 - 2
3. Subtract 2 from 11.
-3.2b + 9
Answer:
13.695 m
Step-by-step explanation:
The assumption made here is that the boat/water interface is essentially frictionless, so that the center of mass of the system remains in the same place as the occupant of the boat moves around.
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We can find the sum of the moments of boat and child about the pier end:
(46 kg)(7.6 m) + (80 kg)((7.6 +9.6/2) m) = 1341.6 kg·m
After the child moves, the center of mass of boat and child is presumed to remain in the same place. If x is the new distance from the pier to the child, the sum of moments is now ...
46x +80(x-4.8)* = 1341.6
126x -384 = 1341.6
x = (1341.6 +384)/126 = 13 73/105 ≈ 13.695 . . . meters
The child is about 13.695 meters from the pier when she reaches the far end of the boat.
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* The center of mass of the boat alone is half its length closer to the pier than is the child, so is located at x-4.8 meters.
Answer:
a(n) = 1(2.5)^(n - 1)
Step-by-step explanation:
The geometric sequence is 1, 2.5, 6.25, 15.625, and so on; the first term is 1. The common ratio is 2.5; each new term is 2.5 times the previous term.
The explicit formula desired is thus a(n) = 1(2.5)^(n - 1)
