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3 years ago

PLEASE HELP! ABC is Isosceles what is AB?

Mathematics

1 answer:

Ilia_Sergeevich [38]3 years ago

4 0

Answer:

AB = 5

Step-by-step explanation:

Since this is an isosceles triangle, you can conclude that there will be two sides of equal length and two angles of equal measurement.

The circular marks on Angle C and Angle A represent congruence between the two angles (The are the same measurement.). From this, you can also conclude that their opposite sides are congruent as well.

From this information you can set up your equation:

AB = BC

Substitute in the corresponding values to solve for x:

3x - 4 = 5x - 10

-2x = -6

x = 3

Substitute x into 3x - 4 to find the length of AB:

AB = 3(3) - 4

AB = 9 - 4

AB = 5

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What is the slant height of a square pyramid with the height of 10cm and base edge 20cm

Klio2033 [76]

Hello!

To find the base length you use the Pythagorean Theorem

$a^{2} + b^{2} = c^{2}$

c is the slant height
a is half the base length
b is the height

Put in the values you know

$10^{2} + 10^{2} = c^{2}$

Square the numbers

$100 + 100 = c^{2}$

Add

$200 = c^{2}$

Take the square root of both sides

$c = \sqrt{200}$

Simplify

$c = 10 \sqrt{2}$

Hope this helps!

6 0

4 years ago

Need helpp fastt plss will give brainliest to who is correct plss helpp!!!!!!!!! It a test I need good grades PLSSSS HELPPPPP!!!

Veseljchak [2.6K]

Answer:Under↓↓↓

Step-by-step explanation:

The unit costs are $0.95 per pound for the 1-pound bag. $0.94 per-pound for the 2-pound bag and $0.92 per pound for the 3-pound bag. The unit cost decreases as the quantity of sugar increases.

0.95/1=0.95

1.88/2=0.94

2.76/3=0.92

Brainliest if Possible pls =D

3 0

3 years ago

Honeydew lemons sell in a market place for $24.95 per box. One box contains 9 melons. How much would you have to pay for 17 melo

Neporo4naja [7]

Answer:

47.13 for 17 melons

Step-by-step explanation:

We can use a ratio to solve

24.95 x dollars

---------------- = ----------------

9 melons 17 melons

Using cross products

24.95 * 17 = 9x

Divide by 9

24.95 * 17/9 = x

47.127777777 = x

Rounding to the nearest cent

47.13 for 17 melons

7 0

4 years ago

Read 2 more answers

In the 1800s, wagon trains traveled west along the oregon trail. A wagon train traveled from missouri to wyoming in 1 2/3 months

strojnjashka [21]

Answer: 2 4/15 months

Step-by-step explanation:

From the question, we are informed that a wagon train traveled from Missouri to Wyoming in 1 2/3 months and from Wyoming to Utah in 3/5 month.

The number of months that it will take the wagon train to travel from Missouri to Utah will be:

= 1 2/3 + 3/5

The common lowest multiple is 15

= 1 10/15 + 9/15

= 1 19/15

= 1 + 1 4/15

= 2 4/15 months

It will take they train 2 4/15 months to travel from Missouri to Utah.

7 0

3 years ago

How many permutations of the 26 letters of the English alphabet do not contain any of the strings fish, rat, or bird

NARA [144]

The number of permutations of the 26 letters of the English alphabet that do not contain any of the strings fish, rat, or bird is 402619359782336797900800000

Let

$\mathcal{E}=\{\text{All lowercase letters of the English Alphabet}\}\\\\B=\overline{\{b,i,r,d\}} \cup \{bird\}\\\\F=\overline{\{f,i,s,h\}} \cup \{fish\}\\\\R=\overline{\{r,a,t\}} \cup \{rat\}\\\\FR=\overline{\{f,i,s,h,r,a,t\}} \cup \{fish,rat\}$

Then

$Perm(\mathcal{E})=\{\text{All orderings of all the elements of } \mathcal{E}\}\\\\Perm(B)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing bird}\}\\\\Perm(F)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing fish}\}\\\\Perm(R)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing rat}\}\\\\Perm(FR)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing both fish and rat}\}\\$

Note that since

$F \cap R=\varnothing$ , $Perm(F)\cap Perm(R)\ne \varnothing$

But since

$B \cap R \ne \varnothing$ , $Perm(B)\cap Perm(R)= \varnothing$

and

$B \cap F \ne \varnothing$ , $Perm(B)\cap Perm(F)= \varnothing$

Since

$|\mathcal{E} |=26 \text{, then, } |Perm(\mathcal{E})|=26! \\\\|B|=26-4+1=23 \text{, then, } |Perm(B)|=23!\\\\|F|=26-4+1=23 \text{, then, } |Perm(F)|=23!\\\\|R|=26-3+1=24 \text{, then, } |Perm(R)|=24!\\\\|FR|=26-7+2=21 \text{, then, } |Perm(FR)|=21!\\$

where $|Perm(X)|=\text{number of possible permutations of the elements of X taking all at once}$

and

$|Perm(F) \cup Perm(R)| = |Perm(F)| + |Perm(R)| - |Perm(FR)|\\= 23!+24!- 21! \text{ possibilities}$

What we are looking for is the number of permutations of the 26 letters of the alphabet that do not contain the strings fish, rat or bird, or

$|Perm(\mathcal{E})|-|Perm(B)|-|Perm(F)\cup Perm(R)|\\= 26!-23!-(23!+24!- 21!)\\= 402619359782336797900800000 \text{ possibilities}$

This link contains another solved problem on permutations:

brainly.com/question/7951365

6 0

3 years ago