Answer:
He spent on 16 minutes
Step-by-step explanation:
Given

per minute

Required
Determine the number of minutes
Let the number of minutes be n
<em>If 1 minute costs $0.5</em>
<em>n minutes would cost $0.5n</em>
The relationship between the given parameters is

Substitute values for each of the above

Solve for 0.5n


Solve for n


<em>He spent on 16 minutes</em>
<em>situation</em><em> </em><em>=</em><em> </em><em>condition</em><em>.</em>
<em>gratitude</em><em> </em><em>=</em><em> </em><em>appreciation</em><em>.</em><em>.</em><em>.</em>
Step-by-step explanation:
4.2y=23.7
y=5.642857
YAYYYYYYYYYYYYYYYYYYY
Answer:
A
Step-by-step explanation:
Recall that for a function to be valid, each input value of x must give us one and only one unique output value for y.
in this case we can see that one of the data sets is (3,-1)
which means that an input of 3 gave an output of -1
but we also see that another data set (3,1)
in this case an input of 3 gave an output of 1.
Because the same x input gives 2 different y outputs, this is not a function.
the answer is A
Answer:
4 liters of 60% solution; 2 liters of 30% solution
Step-by-step explanation:
I like to use a simple, but effective, tool for most mixture problems. It is a kind of "X" diagram as in the attachment.
The ratios of solution concentrations are 3:6:5, so I've used those numbers in the diagram. The constituent solutions are on the left; the desired mixture is in the middle, and the numbers on the other legs of the X are the differences along the diagonals: 6 - 5 = 1; 5 - 3 = 2. This tells you the ratio of 60% solution to 30% solution is 2 : 1.
These ratio units (2, 1) add to 3. We want 6 liters of mixture, so we need to multiply these ratio units by 2 liters to get the amounts of constituents needed. The result is 4 liters of 60% solution and 2 liters of 30% solution.
_____
If you're writing equations, it often works well to let the variable represent the quantity of the greatest contributor—the 60% solution. Let the volume of that (in liters) be represented by v. Then the total volume of iodine in the mixture is ...
... 0.60·v + 0.30·(6 -v) = 0.50·6
... 0.30v = 0.20·6 . . . . subtract 0.30·6, collect terms
... v = 6·(0.20/0.30) = 4 . . . . divide by the coefficient of v
4 liters of 60% solution are needed. The other 2 liters are 30% solution.