All categories

3 years ago

the stained glass below shows bilateral symmetry. The two overlapping squares are congruent. What is the area of the window?

Mathematics

1 answer:

VARVARA [1.3K]3 years ago

5 0

Answer:

116.82 square inches

Step-by-step explanation:

The overall shape is that of a 10-inch square with four triangles attached. Each of those is an isosceles right triangle with leg lengths of 2.9 inches.

The area of the four triangles is ...

total triangle area = 4(1/2)(2.9 in)(2.9 in) = 16.82 in²

The area of the 10-inch square is ...

square area = (10 in)² = 100 in²

Then the total window area is ...

window area = 16.82 in² +100 in²

window area = 116.82 in²

You might be interested in

What is the volume of a rectangle with a height of 7 units a width of 5 units and a length of 8 units

skad [1K]

Answer:

None of the above.

Step-by-step explanation:

7 × 5 × 8 = 280 cubic units

I hope I helped you.

4 0

3 years ago

A bakery sells 3 muffins for every 5 pizza pies.The bakery sold a total of 24 muffins and pizzas pies together.how many of each

Rudiy27

Number of muffins sold=9

and number of pizza pies sold=15

8 0

3 years ago

Simplify: x^0 y^-3 / x^2 Y^-1

natita [175]

x^0 y^-3 / x^2 y^-1
= 1 / x^2 y^-1 (y^3) ...because x^0 = 1 and [(y^-1) (y^3)] = y^2
= 1/(x^2 y^2)

3 0

3 years ago

Read 2 more answers

Chealsea wants to rearrange her room

Llana [10]

Answer:

Good for her.

3 0

3 years ago

Read 2 more answers

The values of 60, 62, and 84 were common to both samples. The three values are identified as outliers with respect to the age-gr

postnew [5]

Answer:

Only 60 is an identified outlier

Step-by-step explanation:

Given

Age group: 40 to 50

$Min = 60$ $Q_1 = 70$ $Median= 73$

$Q_3 = 76$ $Max = 85$

Conditions for outlier

$Value > Q_3 + 1.5 * IQR$

$Value < Q_1 - 1.5 * IQR$

See attachment for complete question

Required

Which of 60, 62 and 84 is an outlier of age grout 40 to 50 years

First, calculate the IQR of group 40 to 50.

This is calculated as:

$IQR = Q_3 - Q_1$

Where:

$Q_3 = 76$ and $Q_1 = 70$

So:

$IQR = 76 - 70$

$IQR = 6$

Next, is to test the outlier conditions on each value (i.e. 60, 62 and 84)

Testing 60

Condition 1

$Value > Q_3 + 1.5 * IQR$

$60 > 76 + 1.5 * 6$

$60 > 76 + 9$

$60 > 85$ --- False

Condition 2

$Value < Q_1 - 1.5 * IQR$

$60 < 70 - 1.5 * 6$

$60 < 70 - 9$

$60 < 61$ --- True

Because one of the conditions is true, then 60 is an outlier of group 40 - 50 years

Testing 62

Condition 1

$Value > Q_3 + 1.5 * IQR$

$62> 76 + 1.5 * 6$

$62 > 76 + 9$

$62 > 85$ --- False

Condition 2

$Value < Q_1 - 1.5 * IQR$

$62 < 70 - 1.5 * 6$

$62 < 70 - 9$

$62 < 61$ --- False

Because both conditions are false, then 62 is not an outlier of group 40 - 50 years

Testing 84

Condition 1

$Value > Q_3 + 1.5 * IQR$

$84> 76 + 1.5 * 6$

$84 > 76 + 9$

$84 > 85$ --- False

Condition 2

$Value < Q_1 - 1.5 * IQR$

$84 < 70 - 1.5 * 6$

$84 < 70 - 9$

$84 < 61$ --- False

Because both conditions are false, then 84 is not an outlier of group 40 - 50 years

5 0

3 years ago