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valentina_108 [34]
2 years ago
15

cain deposited $6033 into savings account 25 years ago the account has an interest rate of 4.2 and the balance is currently $720

8.63 how often does the interest compound
Mathematics
1 answer:
Ksju [112]2 years ago
7 0

Answer:

interest is compounded monthly

Step-by-step explanation:

there is a slight mistake in the question, the future value after 25 years is $17,208.63, not $7,208.63

the future value = present value x (1 + i/a)ⁿᵃ

future value = $17,208.63

present value = $6,033

i/a = 4.2%/a

n x a = 25a

(1 + 0.042/a)²⁵ᵃ = $17,208.63 / $6,033 = 2.852416708

²⁵√(1 + 0.042/a)²⁵ᵃ = ²⁵√2.852416708

(1 + 0.042/a)ᵃ = 1.042818

4.2818% would be the effective interest on the loan, so we can try different options for a. Since the effective interest is higher, I will try first with monthly compounding:

a = 12 (compounded monthly)

(1 + 0.042/12)¹² = (1 + 0.0035)¹² = 1.042818 ✓

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See below

Step-by-step explanation:

You know that he spent 1/3 of his earnings, and then 1/4. After this, he has $28.90. You can write the equation like this:

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B.
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Answer:

1. ΔUJN ≅ ΔUGN by SAS rule of congruency

2. Side Angle Side Rule of congruency

3. JN ≅ GN, ∠JUN ≅ ∠NUG, ∠UNJ ≅ ∠UNG, NU ≅ NU

4. UN bisects angle ∠JUG and UN bisects segment JG

Step-by-step explanation:

The given figure consists of three triangles

1. ΔUJN, 2. ΔUGN, and 3. ΔUJG

Whereby segment UN is perpendicular to segment JG, we have;

ΔUJN and ΔUGN are right triangles

∴ ∠UNJ = ∠UNG = 90° by definition of segment UN being perpendicular to segment JG

NU ≅ NU by reflexive property

Whereby UN bisects ∠JUG and segment JG, we have;

JN = GN by definition of a bisected segment

Therefore, we have;

1. ΔUJN ≅ ΔUGN by SAS rule of congruency

2. Side Angle Side Rule of congruency

3. JN ≅ GN, ∠JUN ≅ ∠NUG, ∠UNJ ≅ ∠UNG, NU ≅ NU

4. UN bisects angle ∠JUG and UN bisects segment JG

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Step-by-step explanation: 252 apex

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5 times 2x minus 40 works because of the distributive property

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