Answer:
22
Step-by-step explanation:
Pretend the 10 values in the first sentence are a,b,c,d,e,f,g,h,i,j
Pretend the addition 5 values is k,l,m,n,o
So the mean of all the 15 data is (a+b+c+d+e+f+g+h+i+j+k+l+m+n+o)/15=20
So the sum of all 15 data is a+b+c+d+e+f+g+h+i+j+k+l+m+n+o=300 since 15(20)=300
Now let's look at the first 10: We have their mean so we can write:
(a+b+c+d+e+f+g+h+i+j)/10=19
so a+b+c+d+e+f+g+h+i+j=190 since 10(19)=190
So that means using our first sum equation and our equation sum equation we have
190+k+l+m+n+o=300
k+l+m+n+o=300-190
k+l+m+n+o= 110
So the average of those 5 numbers mentioned in your problem is 110/5=22
Answer:
32/5
Step-by-step explanation:
K=Keep the first Fraction (You can rewrite 8 as 8/1 for when you multiply across.)
C=Change the Division Sign to a Multiplication Sign
F=Flip the Second Fraction
First, rewrite 1 1/4 as 5/4 (A mixed number can be changed to a fraction by multiplying the outside whole number by the denominator or bottom number of the fraction, then add the new rewritten whole number and the original fractional piece. In this case you would multiply the outside 1 by the bottom 4 and add it to the original 1/4. 4/4+1/4=5/4)
Second, Flip 5/4 to 4/5 and change your equation so it now reads: 8/1 x 4/5
Third, use simple fraction multiplication and multiply across to get 8/1 x 4/5=32/5
Answer:
4x2-9
Step-by-step explanation:
it would be that because the number is in the c acis
C
A line with undefined slope is a vertical line parallel to the y-axis, passing through all points with the same x-coordinate.
For this reason it's equation is x = c
where c is the value of the x-coordinate the line passes through
For (- 3, 5 ) the x-coordinate is - 3, hence
x = - 3 → is the equation of the line
Answer:
The solutions are linearly independent because the Wronskian is not equal to 0 for all x.
The value of the Wronskian is 
Step-by-step explanation:
We can calculate the Wronskian using the fundamental solutions that we are provided and their corresponding the derivatives, since the Wroskian is defined as the following determinant.
Thus replacing the functions of the exercise we get:
Working with the determinant we get
Thus we have found that the Wronskian is not 0, so the solutions are linearly independent.
