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loris [4]
3 years ago
5

Which equation can be solved using the expression StartFraction negative 3 plus-or-minus StartRoot (3) squared + 4 (10) (2) EndR

oot Over 2 (10) EndFraction for x?
A.10x2 = 3x + 2
B.2 = 3x + 10x2
C.3x = 10x2 – 2
D.10x2 + 2 = –3x
Mathematics
2 answers:
fenix001 [56]3 years ago
8 0

Answer:

Its B

Step-by-step explanation:

MakcuM [25]3 years ago
6 0

Answer:

educated guess answer:c

Step-by-step explanation:

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a. The test statistic is 2 and we conclude that the new ad campaign is not signficantly better.

Step-by-step explanation:

They used to be able to sell to 50% of those who saw their ads. Test if the new campaign is better.

At the null hypothesis, we test is it is the same, that is, the proportion is the same.

H_0: p = 0.5

At the alternate hypothesis, we test if it is significantly better, that is, the proportion is above 50%.

H_1: p > 0.5

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

0.5 is tested at the null hypothesis:

This means that \mu = 0.5, \sigma = \sqrt{0.5*0.5} = 0.5

They take a random sample of 100 potential buyers and find that they convinced 60 of these people to buy their product.

This means that n = 100, X = \frac{60}{100} = 0.6

Test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.6 - 0.5}{\frac{0.5}{\sqrt{100}}}

z = 2

The test statistic is 2.

P-value of the test and decision:

The p-value of the test is the probability of finding a sample proportion above 0.6, which is 1 subtracted the by p-value of z = 2.

Looking at the z-table, z = 2 has a p-value of 0.9772.

1 - 0.9772 = 0.0228.

The p-value of the test is 0.0228 > 0.01, which means that we cannot conclude that the new ad campaign is signficantly better, so the correct answer is given by option A.

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Answer: B) reflection over the y-axis

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