Explanation is in the file
tinyurl.com/wpazsebu
Circle: x^2+y^2=121=11^2 => circle with radius 11 and centred on origin.
g(x)=-2x+12 (from given table, find slope and y-intercept)
We can see from the graphics that g(x) will be almost tangent to the circle at (0,11), and that both intersection points will be at x>=11.
To show that this is the case,
substitute g(x) into the circle
x^2+(-2x+12)^2=121
x^2+4x^2-2*2*12x+144-121=0
5x^2-48x+23=0
Solve using the quadratic formula,
x=(48 ± √ (48^2-4*5*23) )/10
=0.5058 or 9.0942
So both solutions are real and both have positive x-values.
Me just so I can ask a question
Answer:
r=8 is a solution. Explanation: To tell whether the given value is a solution to the inequality, we have to solve the inequality. r−3≤9
r=8 is a solution. Explanation: To tell whether the given value is a solution to the inequality, we have to solve the inequality. r−3≤9 Add 3 ... More
Step-by-step explanation:
r=8 is a solution. Explanation: To tell whether the given value is a solution to the inequality, we have to solve the inequality. r−3≤9
r=8 is a solution. Explanation: To tell whether the given value is a solution to the inequality, we have to solve the inequality. r−3≤9 Add 3 ... Morep
Remark
If the lines are parallel, there are no solutions to the system of equations. Start with the equation you know the most about.
x + 6y = 7 Subtract x from both sides
x - x + 6y = 7 - x Combine
6y = - x + 7 Switch and divide by 6
y = -x / 6 + 7/6
The general equation for a line is y = mx + b where m is the slope of the line.
m = - 1/6
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Now look at the second equation
10ay - 5x = 32 Add 5x to both sides
10ay = 5x + 32 Divide by 10a
y = (5/10a)x + 32/(10a)
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Now you must make
5/10a = - 1/6 Cross Multiply
5* 6 = - 10a * 1
30 = - 10a Divide by - 10
a = 30 / - 10
a = - 3
So these two equations will have no solution when a = - 3
