Given lines l, m and n are all parallel and cut by two transversal lines, find the value

Lucy took a taxi from her house to the airport. The taxi company charged a pick-up fee of $3.80 plus $3 per mile. The total fare

prisoha [69]

If you do 39.80/ 3 it would give you 13.2667miles and since the tip was not added that’s when you don’t do anything with that number and 3 because every mile you pay 3$

4 0

3 years ago

Read 2 more answers

At a concession stand, hamburgers are selling at a rate of 160 hamburgers per hour. The table show the rate at which wraps are s

marshall27 [118]

Answer:

hamburgers

Step-by-step explanation:

3 0

3 years ago

Suppose Upper F Superscript prime Baseline left-parenthesis x right-parenthesis equals 3 x Superscript 2 Baseline plus 7 and Upp

Sedaia [141]

It looks like you're given

F'(x) = 3x² + 7

and

F (0) = 5

and you're asked to find F(b) for the values of b in the list {0, 0.1, 0.2, 0.5, 2.0}.

The first is done for you, F (0) = 5.

For the remaining b, you can solve for F(x) exactly by using the fundamental theorem of calculus:

$F(x)=F(0)+\displaystyle\int_0^x F'(t)\,\mathrm dt$

$F(x)=5+\displaystyle\int_0^x(3t^2+7)\,\mathrm dt$

$F(x)=5+(t^3+7t)\bigg|_0^x$

$F(x)=5+x^3+7x$

Then F (0.1) = 5.701, F (0.2) = 6.408, F (0.5) = 8.625, and F (2.0) = 27.

On the other hand, if you're expected to approximate F at the given b, you can use the linear approximation to F(x) around x = 0, which is

F(x) ≈ L(x) = F (0) + F' (0) (x - 0) = 5 + 7x

Then F (0) = 5, F (0.1) ≈ 5.7, F (0.2) ≈ 6.4, F (0.5) ≈ 8.5, and F (2.0) ≈ 19. Notice how the error gets larger the further away b gets from 0.

A better numerical method would be Euler's method. Given F'(x), we iteratively use the linear approximation at successive points to get closer approximations to the actual values of F(x).

Let y(x) = F(x). Starting with x₀ = 0 and y₀ = F(x₀) = 5, we have

x₁ = x₀ + 0.1 = 0.1

y₁ = y₀ + F'(x₀) (x₁ - x₀) = 5 + 7 (0.1 - 0) → F (0.1) ≈ 5.7

x₂ = x₁ + 0.1 = 0.2

y₂ = y₁ + F'(x₁) (x₂ - x₁) = 5.7 + 7.03 (0.2 - 0.1) → F (0.2) ≈ 6.403

x₃ = x₂ + 0.3 = 0.5

y₃ = y₂ + F'(x₂) (x₃ - x₂) = 6.403 + 7.12 (0.5 - 0.2) → F (0.5) ≈ 8.539

x₄ = x₃ + 1.5 = 2.0

y₄ = y₃ + F'(x₃) (x₄ - x₃) = 8.539 + 7.75 (2.0 - 0.5) → F (2.0) ≈ 20.164

4 0

2 years ago

Ines has saved $5. She doubles the amount she saves each week. Does the function have a constant difference or a constant ratio?

salantis [7]

Answer:

The function have a constant ratio

No, it does not represent an exponential function.

Step-by-step explanation:

As given,

Ines has saved $5. She doubles the amount she saves each week.

⇒ In first week she saved = $5

In second week she saved = 2×$5 = $10

In third week she saved = 2×$10 = 20

In fourth week she saved = 2×$20 = 40

and so on..

∴ we get the series

5, 10, 20, 40 ,.......

If the series is given as a, b, c, d, ..... , then

The common difference is defined as d = b-a = c-b

The common ration is defined as r = $\frac{b}{a} = \frac{c}{b}$

Here, in the given question

The series is - 5, 10, 20, 40

This has no common difference , d = 10 - 5 (= 5 )≠ 20 - 10 (= 10)

As 5 ≠ 10

So the function does not define common difference .

Now,

This has common ratio , r = $\frac{10}{5} (=2) = \frac{20}{10}(=2)$

As 2 = 2

So, the function represent common ratio

Now,

The function does not represent an exponential function because it is increased by common ratio.

7 0

3 years ago

A piece of carpet is in the shape of an isosceles trapezoid with a height of 30 inches and bases 40 and 60 inches. What is the a

yaroslaw [1]

30x40x60=72,000. with area you do LxWxH

3 0

3 years ago