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3 years ago

If ab is 2x+3 bc is 3x+5 and ac is 38 what is the value of x

Mathematics

1 answer:

ohaa [14]3 years ago

3 0

Answer:

x would equal 8. because you would add AB and BC together and set it equal to AC

Hoped I helped

Can I get a brainliest

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Can someone please give me the answers to this? ... please ...

Gelneren [198K]

Step-by-step explanation:

the midpoint between 2 points (x1, y1) and (x2, y2) is simply ((x1+x2)/2, (y1+y2)/2).

so,

(9, 7) to (4, -3)

midpoint is ((9+4)/2, (7+ -3)/2) = (13/2, 4/2) = (6.5, 2)

(-7, -5) to (2, 1)

midpoint is ((-7+2)/2, (-5+1)/2) = (-5/2, -4/2) = (-2.5, -2)

now we have the midpoint and need the second point.

(4, 2) over (3, 4) to (x, y)

3 = (4 + x)/2

6 = 4 + x

x = 2

4 = (2 + y)/2

8 = 2 + y

y = 6

(-2, 1) over (-3, 2) to (x, y)

-3 = (-2 + x)/2

-6 = -2 + x

x = -4

2 = (1 + y)/2

4 = 1 + y

y = 3

5 0

2 years ago

Madeline estimated the product of 3.56 and 8.3

ycow [4]

Answer:29.548

Step-by-step explanation:What i know is when they ask you for the product of something there asking you to multiply. So 3.56 x 8.3

4 0

3 years ago

Read 2 more answers

Could I please have the answer to this problem? Could I also please have an explanation, as I'm confused and I don't understand.

tatiyna

Answer:

B is the answer as it's means intersection and none of the numbers intersect x and y

8 0

2 years ago

Read 2 more answers

Two pipes can fill a tank in 19 minutes if both are turned on. If only one is used, it would take 49 minutes longer for the smal

a_sh-v [17]

Answer:

The time taken by smaller pipe to fill the tank alone is 74.2 min

Step-by-step explanation:

Given as :

The time taken by two pipes to fill tank = 19 min

Let the time taken by larger pipe to fill tank = y

And the time taken by smaller pipe to fill tank = x

According to question

The smaller pipe takes 49 minutes longer than larger pipe

I.e x = y + 49

Now,

$\dfrac{1}{x}$ + $\dfrac{1}{y}$ = $\dfrac{1}{49}$

Or, $\dfrac{1}{y + 49}$ + $\dfrac{1}{y}$ = $\dfrac{1}{49}$

Or, $\dfrac{y + 49 + y}{y^{2} + 49 y }$ = $\dfrac{1}{49}$

Or, 2 y + 49 = $\dfrac{y^{2}+49y }{19}$

Or, 19 × ( 2 y + 49 ) = y² + 49 y

Or, 38 y + 931 = y² + 49 y

Or, y² + 49 y - 38 y - 931 = 0

or, y² + 11 y - 931 = 0

Or, Applying quadratic equation method to calculate the value of y

so, y = $\frac{- b \pm \sqrt{b^{2}-4\times a\times c}}{2\times a}$

Or, y = $\frac{- 11 \pm \sqrt{11^{2}-4\times 1\times (-931)}}{2\times 1}$

Or, y = $\frac{- 1 \pm \sqrt{121+3724}}{2}$

or, y = $\frac{- 1 \pm \sqrt{3845}}{2}$

or, y = $\frac{- 1 \pm 62.008}{2}$

∴ y = 25.2 , - 36.5

So, The time taken by larger pipe = y = 25.2 min

and the time taken by smaller pipe to fill the tank = y + 49 = 25.2 + 49 = 74.2 min

Hence The time taken by smaller pipe to fill the tank alone is 74.2 min answer

6 0

3 years ago

In ABC, b = 68 inches, B=65° and C=93º. Find the length of a, to the nearest<br> inches

sp2606 [1]

Answer:

28inches

Step-by-step explanation:

∠A + ∠B + ∠C = 180°

∠A + 65° +93° = 180°

∠A + 158° = 180°

∠A= 180°-158° = 22°

Using Law of Sines

a/sinA= b/sinB

a/sin22= 68 inches/sin65

a/sin22 = 68/0.9063 = 75.03

a = 75.03 x sin 22

a = 75.03 x 0.3746 = 28.106238≈28 inches

3 0

2 years ago