Let
x = larger integer
y = smaller integer
The two integers (x and y) have a sum of 42 which means they add to 42
x+y = 42
solve for y to get
y = 42-x
simply by subtracting x from both sides
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The two integers have a difference of 22. This translates to "subtract the values and the result will be 22", i.e.,
x-y = 22
Plug in y = 42-x. Solve for x
x-y = 22
x-(y) = 22
x - (42-x) = 22
x - 42 + x = 22
2x - 42 = 22
2x - 42+42 = 22+42
2x = 64
2x/2 = 64/2
x = 32
If x = 32, then y is...
y = 42-x
y = 42-32
y = 10
Therefore,
x = 32
y = 10
The final answer is 10
The answer is A 100
because if you divide 1000by 100 your answer would be 100
because of the math
Answer:
24 bags = 21 kg
1.142 bag = 1 kg
About 139 bags = 122 kg
You start off with 24 bags that equal the same amount as 21 kg. You need to find out how many bags of sugar equal the same amount as 122 kg. The first line is a ratio and to find your answer you need to figure out what is 1 kilogram equal to in the amount of bags. You divide both sides by 21 leaving 1.142 bag equal to 1 kilogram. In order to find 122 kilograms, you have to multiply both sides by 122 kilograms which would give you about 139 bags = 122 kilograms.
Your final answer: 139 bags
I hope this helped!
Answer:
Solutions are (3,1) and (4,2)
Step-by-step explanation:
Graph is shown in the attached sheet
Given are two systems of equations and we have to solve them using graph
For graphing let us first prepare table for x and y.
1) 
I line II line
x 0 4.5 3 x 0 2.5 3
y 3 0 1 y -5 0 1
The two lines intersect at (3,1)
Hence solution is (3,1)
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2) 
I line II line
x 0 2 4 x 0 6 4
y 0 1 2 y 3 0 2
The two lines intersect at (4,2)
Hence solution is (4,2)
