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drek231 [11]
3 years ago
12

What is the solution to this linear system? Enter a value in each box to create an ordered pair,

Mathematics
1 answer:
sergejj [24]3 years ago
7 0

Given:

Consider the below figure attached with this question.

To find:

The solution to this linear system.

Solution:

From the below graph it is clear that both lines intersect each other at point (2,3).

Here,

x-coordinate = 2

y-coordinate = 3

Therefore, the solution to the given system is (2,3).

Hence, the required answer for first blank is 2 and for second blank is 3.

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strojnjashka [21]
4.16=416/100
416/100=4•104/4•25
=104/25
4.16=104/25
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3 years ago
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The perimeters of the square and the triangle shown below are equal. What is the value of x?
Rudiy27
Perimeter is the sum of all the sides. So we can set up an equation:

\sf 3x+1+3x+1+3x+1+3x+1=2x+8+x+8+4x+2

Now solve for 'x', combine like terms:

When it comes to terms with variables it's just like normal addition but we keep the variable:

\sf 3x+3x+3x+3x=12x
\sf 2x+x+4x=7x

So we have:

\sf 12x+1+1+1+1=7x+8+8+2

Add:

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Subtract 7x to both sides:

\sf 5x+4=18

Subtract 4 to both sides:

\sf 5x=14

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\boxed{\sf x=2.8}
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3 years ago
What is the range of the function for the given domain
AleksAgata [21]

Answer:

thethe answer is the 3rd one

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3 years ago
Which expression is equivalent to square root a^7
FinnZ [79.3K]

Answer is d

Step-by-step explanation:

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Use the information provided to write the equation of the circle Center: (10,-9) Point on Circle: (12,-13)
Zielflug [23.3K]

Answer:

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Step-by-step explanation:

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(x - h)² + (y - k)² = r²

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r = √(x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = (10, - 9) and (x₂, y₂ ) = (12, - 13)

r = \sqrt{(12-10)^2+(-13+9)^2}

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(x - 10)² + (y - (- 9))² = (\sqrt{20})², that is

(x - 10)² + (y + 9)² = 20

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3 years ago
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