1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
nikdorinn [45]
3 years ago
11

How many terms are in 2x^3-5x^2-2x+12

Mathematics
2 answers:
den301095 [7]3 years ago
7 0
Answer

the answer is 4

hope it helped
Mice21 [21]3 years ago
5 0
Answer:

4

Explanation:

You might be interested in
The average of 6 number is 4. A seventh number is added and the new average is 5. Find the seventh number
KatRina [158]
The seventh number would have to be 11
6 0
3 years ago
There are two hotels that want to offer their guests Internet access. The hotels have different service Plans that charge the us
Jet001 [13]

Answer:

Slope is the rate per minute

1) $1 per minute

2) $0.65 per minute

y-intercept is the fixed amount which must be paid regardless of how much time internet is used

1) $5

2) $7

3 0
3 years ago
Van guessed on all 8 questions of a multiple-choice quiz. Each question has 4 answer choices. What is the probability that he go
aleksandr82 [10.1K]

Answer:

0.267

Step-by-step explanation:

This can be solved using the binomial probability formula which is:

P(success)=nCk*p^{k}(1-p)^{n-k}

Where

n is total number of trials (here, the total number of questions is 8, so n = 8)

k is the number of attempts we are looking for (here, we want to find probability of 1 question correct, so k = 1)

p is the probability of success (here, success is getting a questions right. Since there are 4 choices and 1 is right, probability of right = 1/4)

<em>Plugging all the info into the formula we get:</em>

<em>P(success)=nCk*p^{k}(1-p)^{n-k}\\P(1QuestionRight)=8C1*(\frac{1}{4})^{1}(1-\frac{1}{4})^{8-1}\\P(1QuestionRight)=\frac{8!}{(8-1)!*1!}(\frac{1}{4})(\frac{3}{4})^7\\P(1QuestionRight)=\frac{8!}{7!*1!}(\frac{1}{4})(\frac{3}{4})^7\\P(1QuestionRight)=8(\frac{1}{4})(\frac{3}{4})^7\\=0.267</em>

<em />

<em>Second choice is right.</em>

5 0
4 years ago
A campus program evenly enrolls undergraduate and graduate students. If a random sample of 4 students is selected from the progr
ratelena [41]

Answer:

B. 0.0625

Step-by-step explanation:

Given that the program has graduated and undergraduates enrolled,

Let the probability of selecting a graduate = p(g)

And the probability of selecting an undergraduate = p(u)

p(g) = p(u) = 50% = 0.5

Therefore,

Probability of selecting 4 students who are undergraduates

=p(u)p(u)p(u)p(u)

= 0.5 × 0.5 × 0.5 × 0.5

= 0.0625

The right option is B

3 0
4 years ago
What is the range of this data set?<br><br> {10, 4, 1, 7, 4, 6, 5, 9}
Andru [333]

Answer:

9

Step-by-step explanation:

Range is just the difference between the highest and lowest number. So, in this case it should be 10 - 1.

5 0
4 years ago
Read 2 more answers
Other questions:
  • A spinner is divided into sections of equal size, some of which are red, some are blue, and the remaining are green. The probabi
    12·2 answers
  • Is this question proportional? why or why not
    15·1 answer
  • A 3491 by 3491 square has its length decreased by 60 and its width increased by 60. By how much does its area change?
    14·1 answer
  • Find the missing side length
    6·1 answer
  • What statement is true about perpendicular lines​
    11·1 answer
  • Please help!<br> Solve for x. Round to the nearest tenth of a degree, if necessary.
    8·1 answer
  • What is the value of x?
    9·1 answer
  • Find the discount rate if the retail price of an item is $70 and its sale price is $42.
    8·2 answers
  • Angel believes that a vertical shift of the parent function f(x)=x^2 will always change the domain of the function do you agree
    5·1 answer
  • which of the following is written in scientific notation? A. 82,000,00 B. (6.3) (10^6) C. (2874) (10^6) D. (648.5) (10^6)​
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!