Answer:
Step-by-step explanation
But the question does not say exactly what should be solve for.
The given equations are:
1) 2y = -x + 9
⇒ x = 9-2y
2) 3x - 6y = -15
⇒3x = 6y - 15
x = 2y - 5
Equating the values of x, we get:
9 - 2y = 2y - 5
9 + 5 = 4y
14 = 4y
y = 3.5
Using this value of y in equation 1 we get:
x = 9 - 2(3.5) = 2
So, the solution set is (2, 3.5)
PLEASE give a picture so we know what your talk about........
To find the time at which both balls are at the same height, set the equations equal to each other then solve for t.
h = -16t^2 + 56t
h = -16t^2 + 156t - 248
-16t^2 + 56t = -16t^2 + 156t - 248
You can cancel out the -16t^2's to get
56t = 156t - 248
=> 0 = 100t - 248
=> 248 = 100t
=> 2.48 = t
Using this time value, plug into either equation to find the height.
h = 16(2.48)^2 + 56(2.48)
Final answer:
h = 40.4736
Hope I helped :)
Answer:
3x^7 / y
Step-by-step explanation:
√63x^15y^9/√7xy^11
= √ [(63/7) x^(15-1) y^(9-11)
= √9x^14y^-2
= √9x^14 / y^2
= 3x^7 / y
