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Lesechka [4]
3 years ago
15

Two drivers, Alison and Kevin, are participating in a drag race. Beginning from a standing start, they each proceed with a const

ant acceleration. Alison covers the last 1/4 of the distance in 3 seconds, whereas Kevin overs the last 1/3 of the distance in 4 seconds. Who wins and by how much time?
Mathematics
1 answer:
Vilka [71]3 years ago
4 0

Answer:

Alison wins against Kevin by 0.93 s

Step-by-step explanation:

Alison covers the last 1/4 of the distance in 3 seconds, at a constant acceleration a_a, we have the following equation of motion

s/4 = a_at_a^2/2

where s (m) is the total distance, ta = 3 s is the time

s = 4a_a3^2/2 = 18a_a

a_a = s/18

Similarly, Kevin overs the last 1/3 of the distance in 4 seconds, at a constant acceleration a_k, we have the following equation of motion:

s/3 = a_kt_k^2/2

tk = 4 s is the time

s = 3a_k4^2/2 = 24a_k

a_k = s/24

Since a_a = s/18 we can conclude that a_a > a_k, so Alison would win.

The time it takes for Alison to cover the entire track

s = a_aT_a^2/2

T_a^2 = 2s/a_a = 2s/(s/18) = 36

T_a = \sqrt{36} = 6 s

The time it takes for Kevin to cover the entire track

s = a_kT_k^2/2

T_k^2 = 2s/a_k = 2s/(s/24) = 48

T_a = \sqrt{48} = 6.93 s

So Alison wins against Kevin by 6.93 - 6 = 0.93 s

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Can someone plz help me with this!
asambeis [7]

Answer:

(arranged from top to bottom)

System #3, where x=6

System #1, where x=4

System #7, where x=3

System #5, where x=2

System #2, where x=1

Step-by-step explanation:

System #1: x=4

2x+y=10\\x-3y=-2

To solve, start by isolating your first equation for y.

2x+y=10\\y=-2x+10

Now, plug this value of y into your second equation.

x-3(-2x+10)=-2\\x+6x-30=-2\\7x=28\\x=4

System #2: x=1

x+2y=5\\2x+y=4

Isolate your second equation for y.

2x+y=4\\y=-2x+4

Plug this value of y into your first equation.

x+2(-2x+4)=5\\x+(-4x)+8=5\\x-4x+8=5\\-3x=-3\\x=1

System #3: x=6

5x+y=33\\x=18-4y

Isolate your first equation for y.

5x+y=33\\y=-5x+33

Plug this value of y into your second equation.

x=18-4(-5x+33)\\x=18+20x-132\\-19x=-114\\x=6

System #4: all real numbers (not included in your diagram)

y=13-2x\\8x+4y=52

Plug your value of y into your second equation.

8x+4(13-2x)=52\\8x+52-8x=52\\0=0

<em>all real numbers are solutions</em>

System #5: x=2

x+3y=5\\6x-y=11

Isolate your second equation for y.

6x-y=11\\-y=-6x+11\\y=6x-11

Plug in your value of y to your first equation.

x+3(6x-11)=5\\x+18x-33=5\\19x=38\\x=2

System #6: no solution (not included in your diagram)

2x+y=10\\-6x-3y=-2

Isolate your first equation for y.

2x+y=10\\y=-2x+10

Plug your value of y into your second equation.

-6x-3(-2x+10)=-2\\-6x+6x-30=-2\\-30=-2

<em>no solution</em>

System #7: x=3

y=10+x\\2x+3y=45

Plug your value of y into your second equation.

2x+3(10+x)=45\\2x+30+3x=45\\5x=15\\x=3

3 0
3 years ago
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Arlecino [84]

Answer:

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v = 28.5/.95

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Step-by-step explanation:

7 0
3 years ago
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balu736 [363]

Answer:

$3.296

Step-by-step explanation:

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6 0
3 years ago
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rusak2 [61]

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6 0
4 years ago
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marishachu [46]

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hope this helped

plz mark brainliest so

i can rank up

;p <3

8 0
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