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3 years ago

I need help right now (25 points on whoever gets this right)

Mathematics

1 answer:

meriva3 years ago

5 0

The answer is 37% because it depends on how many day are cancelled throughout the year of school

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If bd = 7x-10, bc = 4x-29, and cd = 5x-9, find each value

Airida [17]

Answer:

$bd=88$ , $bc=27$ , $cd=61$

Step-by-step explanation:

In this problem we have that

$bd=bc+cd$

we have

$bd=7x-10$

$bc=4x-29$

$cd=5x-9$

substitute the values and solve for x

$7x-10=(4x-29)+(5x-9)$

Group terms that contain the same variable in the right sides

$7x-10=(4x+5x)+(-29-9)$

Combine like terms in the right side

$7x-10=9x-38$

$9x-7x=-10+38$

$2x=28$

$x=14$

Find the value of bd

$bd=7(14)-10=88$

Find the value of bc

$bc=4(14)-29=27$

Find the value of cd

$cd=5(14)-9=61$

4 0

4 years ago

Given the equation y = 3x − 4, what is the value of x when y = 5? A) 3 B) 6 C) 9 D) 12

timurjin [86]

Answer:

Step-by-step explanation:

the equation would be 5 = 3(3) - 4

which is 9 - 4 = 5

7 0

4 years ago

A rectangular box has three of its faces on the coordinate planes and one vertex in the first octant on the paraboloid z=100−x2−

LuckyWell [14K]

The volume as a function of the location of that vertex is

... v(x, y, z) = x·y·z = x·y·(100-x²-y²)

This function is symmetrical in x and y, so will be a maximum when x=y. That is, you wish to maximize the function

... v(x) = x²(100 -2x²) = 2x²(50-x²)

This is a quadratic in x² that has zeros at x²=0 and x²=50. It will have a maximum halfway between those zeros, at x²=25. That maximum volume is

... v(5) = 2·25·(50-25) = 1250

The maximum volume of the box is 1250 cubic units.

7 0

3 years ago

Gerard concluded that the triangle with sides StartRoot 95 EndRoot feet, 8 feet, and StartRoot 150 EndRoot cannot be used as a b

Pachacha [2.7K]

Answer:

Check explanations for answer

Step-by-step explanation:

Here, we want to find out how Gerard came to the conclusion

For him to arrive at this conclusion, then we should consider the lengths given if they form a right triangle and are suitable for the building frame

From the lengths that we have

If we square the longest length, then the sum of the squares of the two other lengths should be the same as it is

This is in obedience to Pythagoras’ theorem

However, this does not hold

√(150)^2 is not equal to 8^2 + (√(95))^2)

and so since this does not work, then the triangle is not right-angled and cannot be use as the frame

3 0

3 years ago

Help please ASAP for 12pts

Phoenix [80]

I believe the anwser is l

6 0

4 years ago