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Nataly [62]
3 years ago
10

6n+n+14=0 i need the math

Mathematics
1 answer:
Fofino [41]3 years ago
6 0
Let's solve your equation step-by-step.<span><span><span><span>6n</span>+n</span>+14</span>=0</span>

Step 1: Simplify both sides of the equation.<span><span><span><span>6n</span>+n</span>+14</span>=0</span><span>Simplify: (Show steps)</span><span><span><span>7n</span>+14</span>=0</span>

Step 2: Subtract 14 from both sides.<span><span><span><span>7n</span>+14</span>−14</span>=<span>0−14</span></span><span><span>7n</span>=<span>−14</span></span>

Step 3: Divide both sides by 7.<span><span><span>7n</span>7</span>=<span><span>−14</span>7</span></span><span>n=<span>−2</span></span>

Answer:<span>n=<span>−<span>2</span></span></span>
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Step-by-step explanation:

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Step-by-step explanation:

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2 years ago
Kelko will rent a car for the weekend. She can choose one of two plans. The first plan has an initial fee of $57 and cost an add
Delicious77 [7]

Questions (contd)

(a) For what amount of driving do the two plans cost the same?

(b) What is the cost when the two plans cost the same?

Answer:

(a) 100 miles

(b) $65

Step-by-step explanation:

Given

Plan 1:

Initial\ Fee = \$57

Additional = \$0.08 per mile

Plan 2:

Initial\ Fee = \$50

Additional = \$0.10 per mile

Solving (a): Number of miles when both plans are equal

Represent the distance with x and the cost with y

So:

Plan 1:

y = 57 + 0.08 * x

Plan 2:

y = 50 + 0.10 * x

To solve (a), we equate both plans together; i.e.

y = y

57 + 0.08x = 50 + 0.10x

Collect Like Terms

0.08x - 0.10x= 50 - 57

-0.02x= -2

Solve for x

x = -2/-0.02

x = 100

Hence, 100 mile would cost both plans the same

Solving (b): Cost when both plans are the same:

In this case, we simply substitute 100 for x in any of the y equation.

y = 57 + 0.08 * x

y = 57 + 0.08 * 100

y = 57 + 8

y = 65

<em>Hence, the amount is $65</em>

7 0
2 years ago
Let's make the most liked question in the whole website
natali 33 [55]

Answer:

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7 0
3 years ago
Read 2 more answers
Show the work please
Kay [80]

Answer:

1) (x + 3)(3x + 2)

2) x= +/-root6 - 1 by 5

Step-by-step explanation:

3x^2 + 11x + 6 = 0 (mid-term break)

using mid-term break

3x^2 + 9x + 2x + 6 = 0

factor out 3x from first pair and +2 from the second pair

3x(x + 3) + 2(x + 3)

factor out x+3

(x + 3)(3x + 2)

5x^2 + 2x = 1 (completing squares)

rearrange the equation

5x^2 + 2x - 1 = 0

divide both sides by 5 to cancel out the 5 of first term

5x^2/5 + 2x/5 - 1/5 = 0/5

x^2 + 2x/5 - 1/5 = 0

rearranging the equation to gain a+b=c form

x^2 + 2x/5 = 1/5

adding (1/5)^2 on both sides

x^2 + 2x/5 + (1/5)^2 = 1/5 + (1/5)^2

(x + 1/5)^2 = 1/5 + 1/25

(x + 1/5)^2 = 5 + 1 by 25

(x + 1/5)^2 = 6/25

taking square root on both sides

root(x + 1/5)^2 = +/- root(6/25)

x + 1/5 = +/- root6 /5

shifting 1/5 on the other side

x = +/- root6 /5 - 1/5

x = +/- root6 - 1 by 5

x = + root6 - 1 by 5 or x= - root6 - 1 by 5

4 0
3 years ago
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