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alex41 [277]
3 years ago
11

The Academic Computing Center has five trainers available in its computer labs to provide training sessions to students. Assume

that the design capacity of the system is 1900 students per semester and that effective capacity equals 90% of design capacity. If the number of students who actually got their orientation session is 1500, what is the efficiency of the system?
Mathematics
1 answer:
kondor19780726 [428]3 years ago
7 0

Answer:

87.72%

Step-by-step explanation:

Data provided in the question:

Design capacity of the system = 1900 students per semester

Effective capacity = 90% of design capacity

Actual number of students = 1500

Now,

Efficiency = [ [ Actual capacity ] ÷ [ Effective capacity ] ] × 100%

also,

Effective capacity = 90% of 1900

= 0.90 × 1900

= 1710

Efficiency = [ 1500 ÷ 1710 ] × 100%

= 0.8772 × 100%

= 87.72%

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2(x+11) = -26 show all work pls
Degger [83]

Answer:

x = -24

Step-by-step explanation:

First, distribute 2 to all terms within the parenthesis:

2(x + 11) =

2 * x = 2x

2 * 11 = 22

2x + 22 = -26

Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS. PEMDAS is the order of operations, and stands for:

Parenthesis

Exponents (& Roots)

Multiplications

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Additions

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~

First, subtract 22 from both sides of the equation:

2x + 22 (-22) = -26 (-22)

2x = -26 - 22

2x = -48

Next, divide 2 from both sides of the equation:

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x = -24 is your answer.

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2 years ago
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TEA [102]

Answer:

C) 60

Step-by-step explanation:

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4 0
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Read 2 more answers
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scoundrel [369]

Answer:

  9^{\frac{3}{2}}=\sqrt{9^3}=27

Step-by-step explanation:

The fractional exponent m/n is often translated to radical form as ...

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In this case, I find it easier to evaluate as ...

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snow_lady [41]

Answer:

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Step-by-step explanation:

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