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4 years ago

I need help with this question

Mathematics

1 answer:

Trava [24]4 years ago

8 0

The Answer is D ( Four Times Z subtracted by V cubed) Hope I helped
plus you go to OHDLEA?

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5th grade math. correct answer will be marked brainliest

Basile [38]

Answer:

Step-by-step explanation:

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3 years ago

Lannie ordered 12 copies of the same book for his book club members.The book cost $19 each, and the order has a $15 shipping cha

Dmitrij [34]

That will have 12x19+15 which equals 243 dollars.

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4 years ago

There are 269 basketball

Vesna [10]

Simple division. 269/48=5.60416666667. You probably cannot put decimals, so round to 6.

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4 years ago

Read 2 more answers

Sebastian a store manager earns 125.20 for eight hours of work How much does he earn per hour A $0.07 B $1,001.60 C $14.65 D$15.

Diano4ka-milaya [45]

Answer

The correct answer is D. $ 15.65

Step-by-step explanation:

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3 years ago

If you are dealt five cards from a shuffled deck of 52 cards find the probability of getting three queens and two kings

dexar [7]

The probability of getting three queens and two kings is $\frac{1}{1082900}$

Solution:

Given that , you are dealt five cards from a shuffled deck of 52 cards

We have to find the probability of getting three queens and two kings

Now, we know that, in a deck of 52 cards, we will have 4 queens and 4 kings.

$\text { probability of an event }=\frac{\text { favarable possibilities }}{\text { number of possibilities }}$

Probability of first queen:

$\text { Probability for } 1^{\text {st }} \text { queen }=\frac{4}{52}=\frac{1}{13}$

Probability of second queen:

$\text { Plobability for } 2^{\text {nd }} \text { queen }=\frac{3}{51}=\frac{1}{17}$

Here we used 3 for favourable outcome, since we already drew 1 queen out of 4

And now number of outcomes = 52 – 1 = 51

Probability of third queen:

Similarly here favorable outcome = 2, since we already drew 2 queen out of 4

And now number of outcomes = 51 – 1 = 50

$\text { Probability of } 3^{\text {rd }} \text { queen }=\frac{2}{50}=\frac{1}{25}$

Probability for first king:

Here kings are 4, but overall cards are 49 as 3 queens are drawn

$\text { probability for } 1^{\text {st }} \text { king }=\frac{4}{49}$

Probability for second king:

Here, kings are 3 and overall cards are 48 as 3 queens and 1 king are drawn

$\text { probability of } 2^{\text {nd }} \text { king }=\frac{3}{48}=\frac{1}{16}$

And, finally the overall probability to get 3 queens and 2 kings is:

$=\frac{1}{13} \times \frac{1}{17} \times \frac{1}{25} \times \frac{4}{49} \times \frac{1}{16}=\frac{4}{4331600}=\frac{1}{1082900}$

Hence, the probability is $\frac{1}{1082900}$

7 0

3 years ago