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Masja [62]
3 years ago
10

What is the general form of the equation for the given circle centered at O(0, 0)?

Mathematics
1 answer:
Katyanochek1 [597]3 years ago
8 0
It is called the origin and I am not exactly sure what you mean by 'general form of the equation'.
You might be interested in
The range of five numbers is 10, the mean is 13.6, the median is 14,
denis23 [38]

Answer:

8 13 14 15 18.

Step-by-step explanation:

The median (the middle number) is 14 so we have

x x 14 x x       where x is a single number with each number being different (as there is no mode).

The mean is 13.6 so we have the total numbers

= 13.6 * 5 = 68.

The  4 numbers left must total 68-14 = 54 and the difference between the highest and lowest is 10.

I sense that the lowest and highest will add up to  about 1/2 of 54 so:

Try 8 and 18 for these last 2 numbers

The list would be 8 x 14 x 18.

The 2 numbers left will add up to 54 - 26 = 28 . One of these must be < 14 and the other > 14.  13 and 15 would fit.

So a possible data set  is:

8 13 14 15 18.

7 0
3 years ago
At a certain gas station, 40% of the customers use regular gas (A1), 35% use plus gas (A2), and 25% use premium (A3). Of those c
grandymaker [24]

Answer:

a.)

P( A₂ ∩ B ) = P(B | A₂) × P(A₂)

P( A₂ ∩ B ) = 0.40 × 0.35

P( A₂ ∩ B ) = 0.14

b.)

P(B) = P( A₁ ∩ B )  + P( A₂ ∩ B ) + P( A₃ ∩ B )

P(B) = 0.08 + 0.14 + 0.125

P(B) = 0.345

c.)

For regular gas:

P(A₁ | B) = P( A₁ ∩ B ) / P(B)

P(A₁ | B) = 0.08 / 0.345

P(A₁ | B) = 0.232

For plus gas:

P(A₂ | B) = P( A₂ ∩ B ) / P(B)

P(A₂ | B) = 0.14 / 0.345

P(A₂ | B) = 0.406

For premium gas:

P(A₃ | B) = P( A₃ ∩ B ) / P(B)

P(A₃ | B) = 0.125 / 0.345

P(A₃ | B) = 0.362

Step-by-step explanation:

We are given the following information

40% of the customers use regular gas (A2)

P(A₁) = 0.40

35% use plus gas (A2)

P(A₂) = 0.35

25% use premium (A3)

P(A₃) = 0.25

Of those customers using regular gas, only 20% fill their tanks (event B).

P(B | A₁) = 0.20

Of those customers using plus, 40% fill their tanks

P(B | A₂) = 0.40

Whereas of those using premium, 50% fill their tanks.

P(B | A₃) = 0.5

a) What is the probability that the next customer will request plus gas and fill their tank?

We are asked to find P(A₂ ∩ B) = ?

Recall that Multiplicative law of probability is given by

P( A₂ ∩ B ) = P(B | A₂) × P(A₂)

P( A₂ ∩ B ) = 0.40 × 0.35

P( A₂ ∩ B ) = 0.14

b) What is the probability that the next customer fills the tank?

We are asked to find P(B) = ?

P(B) = P( A₁ ∩ B )  + P( A₂ ∩ B ) + P( A₃ ∩ B )

P( A₂ ∩ B ) is already calculated, we need to calculate

P( A₁ ∩ B ) and P( A₃ ∩ B )

So,

P( A₁ ∩ B ) = P(B | A₁) × P(A₁)

P( A₁ ∩ B ) = 0.20 × 0.40

P( A₁ ∩ B ) = 0.08

P( A₃ ∩ B ) = P(B | A₃) × P(A₃)

P( A₃ ∩ B ) = 0.50 × 0.25

P( A₃ ∩ B ) = 0.125

Finally,

P(B) = P( A₁ ∩ B )  + P( A₂ ∩ B ) + P( A₃ ∩ B )

P(B) = 0.08 + 0.14 + 0.125

P(B) = 0.345

c) If the next customer fills the tank, what is the probability that the regular gas is requested? Plus? Premium

For regular gas:

P(A₁ | B) = P( A₁ ∩ B ) / P(B)

P(A₁ | B) = 0.08 / 0.345

P(A₁ | B) = 0.232

For plus gas:

P(A₂ | B) = P( A₂ ∩ B ) / P(B)

P(A₂ | B) = 0.14 / 0.345

P(A₂ | B) = 0.406

For premium gas:

P(A₃ | B) = P( A₃ ∩ B ) / P(B)

P(A₃ | B) = 0.125 / 0.345

P(A₃ | B) = 0.362

5 0
4 years ago
Please help me i need an answer
Alexeev081 [22]
Option b $ 220 is answer
5 0
3 years ago
Read 2 more answers
3.
rewona [7]

Answer:

B. exponential; y = 91 • 0.77x

Step-by-step explanation:

I just substituted the x on all of them and only one got the correct y which is B.

...............................................................................................................................................

The Answer is B.

y=91*0.77^x

...............................................................................................................................................

4 0
3 years ago
a map of Texas uses the scale of 1.5 to represent 60 miles the distance between corpus Christi to Houston is 60 miles what is th
Mama L [17]

Answer:ahhhh

Step-by-step explanation:

I hope this helps

4 0
3 years ago
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