Answer: The right answer is 2
Step-by-step explanation:
- Write out the expression
T1; a = 0.3 ------------ (I)
T8; ar^7 = 38.4 ------------ (ii)
Substituting for 'a' in the second equation, we have;
0.3r^7 = 38.4
0.3r^7 = 38.4
Divide both sides by 0.3
r^7 = 38.4/0.3
r^7 = 128
r = (128)^1/7
r = 2
Answer:
The answer is .393. Hope this helps.
The solution to this is 3(8)-3(9).
-18 because a negative number times positive is negative.
~JZ
Answer:
0.347% of the total tires will be rejected as underweight.
Step-by-step explanation:
For a standard normal distribution, (with mean 0 and standard deviation 1), the lower and upper quartiles are located at -0.67448 and +0.67448 respectively. Thus the interquartile range (IQR) is 1.34896.
And the manager decides to reject a tire as underweight if it falls more than 1.5 interquartile ranges below the lower quartile of the specified shipment of tires.
1.5 of the Interquartile range = 1.5 × 1.34896 = 2.02344
1.5 of the interquartile range below the lower quartile = (lower quartile) - (1.5 of Interquartile range) = -0.67448 - 2.02344 = -2.69792
The proportion of tires that will fall 1.5 of the interquartile range below the lower quartile = P(x < -2.69792) ≈ P(x < -2.70)
Using data from the normal distribution table
P(x < -2.70) = 0.00347 = 0.347% of the total tires will be rejected as underweight
Hope this Helps!!!
